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Airida [17]
2 years ago
6

Please Help Me Balance The equation!! will mark brainliest

Chemistry
2 answers:
Delvig [45]2 years ago
8 0

Answer:

XCl2 + 2 AgNO3 = X(NO3)2 + 2 AgCl

Explanation:

i ran this through a calculator

Lina20 [59]2 years ago
5 0

Answer: XCl2(aq) + 2 AgNO3(aq) ---> X(NO3)2(aq) + 2 AgCl(s)

Explanation:

Hehe I remembered how...

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How many atoms are in 294 g of copper?
mote1985 [20]

Answer

2.1 x 10 ^23

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7 0
2 years ago
1(a). What is the solubility of calcium chloride (CaCl2) at 5°C?
In-s [12.5K]

Answer:

60 g/100 g water  

Explanation:

Find 5 °C on the horizontal axis.

Draw a line vertically from that point until you reach the solubility curve for CaCl₂.  

Then draw a horizontal line from there to the vertical axis.

The solubility of CaCl₂ is 60 g/100 g water.

7 0
2 years ago
Problem Page Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.2 g o
stich3 [128]

Answer: 0.0 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of butane

\text{Number of moles}=\frac{5.2g}{58.12g/mol}=0.09moles

b) moles of oxygen

\text{Number of moles}=\frac{32.6g}{32g/mol}=1.02moles

2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O

According to stoichiometry :

2 moles of butane require 13 moles of O_2

Thus 0.09 moles of butane will require =\frac{13}{2}\times 0.09=0.585moles  of O_2

Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.

Thus all the butane will be consumed and 0.0 grams of butane will be left.

7 0
2 years ago
Please select the word from the list that best fits the definition
sammy [17]
Pretty sure it’s ,B. Microscope!
8 0
2 years ago
Need help please!
MaRussiya [10]

Answer:

Solid

Explanation:

Me Brainly

4 0
2 years ago
Read 2 more answers
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