The balanced chemical equation for the Haber-Bosch process is N₂(g) + 3H₂(g) → 2NH₃(g). The Haber-Bosch process played a significant role in boosting agriculture back in the day. It paved the way for the industrial production of ammonia which is used in the manufacture of fertilizers. The process involves reacting atmospheric N₂ with H₂ using a metal catalyst under high temperature and pressure.
The answer is 6 ft 10 inches in millimeters (mm) is 0.833 ft.
Given,
The center of the school's basketball team is 6 ft 10 inches tall.
We have to convert the height of the player from feet and inches to feet.
Using the conversion factor,
1 ft = 12 inches
or, 12inches/ 1 ft
Converting 6ft 10 inches to ft, we get;
10 inches × 1 ft/ 12inches
= 0.833 ft
Therefore 6 ft 10 inches in millimeters (mm) is 0.833 ft.
Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.
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For an aqueous solution of MgBr2, a freezing point depression occurs due to the rules of colligative properties. Since MgBr2 is an ionic compound, it acts a strong electrolyte; thus, dissociating completely in an aqueous solution. For the equation:
ΔTf<span> = (K</span>f)(<span>m)(i)
</span>where:
ΔTf = change in freezing point = (Ti - Tf)
Ti = freezing point of pure water = 0 celsius
Tf = freezing point of water with solute = ?
Kf = freezing point depression constant = 1.86 celsius-kg/mole (for water)
m = molality of solution (mol solute/kg solvent) = ?
i = ions in solution = 3
Computing for molality:
Molar mass of MgBr2 = 184.113 g/mol
m = 10.5g MgBr2 / 184.113/ 0.2 kg water = 0.285 mol/kg
For the problem,
ΔTf = (Kf)(m)(i) = 1.86(0.285)(3) = 1.59 = Ti - Tf = 0 - Tf
Tf = -1.59 celsius
Species are the smallest groups. A species consists of all the animals of the same type, who are able to breed and produce young of the same kind. For example, while any two great white sharks are in the same species, as are any two makos, great whites and makos are in different species (since they can't interbreed Answer :SPECIES
Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J
Explanation:
1) Data:
Water ⇒ C = 1 cal/g°C
m = 65.8 g
Ti = 31.5°C
Tf = 36.9°C
Heat, Q = ?
2) Formula:
Q = mCΔT
3) Calculations:
Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal
4) You can convert from calories to Joules using the conversion factor:
1 cal = 4.18 J
⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J
