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Vanyuwa [196]
3 years ago
8

What is the equation of the line with a y-intercept of 4 and a point (8,8)? ​

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer:

The equation of the line with a y-intercept of 4 and a point (8,8) is y=\frac{1}{2} *x+4

Step-by-step explanation:

A linear equation can be expressed in the form

y = m * x + b

where x and y are coordinates of a point, m is the slope and b is the y-intercept. Since this equation describes a line in terms of its slope and its y-intercept, this equation is said to be in its slope-intercept form.

Graphically this equation represents a line.

In this case, you know:

  • The point (x,y)=(8,8)
  • Y-intercept= 4

Replacing:

8=m*8 +4

Solving:

8-4=m*8

4=m*8

4÷8= m

m=\frac{1}{2}

Then, <u><em>the equation of the line with a y-intercept of 4 and a point (8,8) is </em></u>y=\frac{1}{2} *x+4<u><em></em></u>

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Step-by-step explanation:

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