<span>C6H12 = 6x12 + 6x1 = 78.
The equation indicates that 2x78 = 156g benzene will produce 6542kJ.
Using proportions you can then calculate that
x/6542kJ = 7.9g / 156g
x = 331.3kJ = 331300J.
heat = mass x ΔT x 4.18J/g°
ΔT = 331300J / (5691g x 4.18J/g°) = 13.9°
final temp = 21 + 14° = 35°C</span>
Lets name the unknown metal as M. Cation would be M³⁺.
the molecular formula of the compound is M₂(SO₄)₃
the mass of one mole - (molar mass of M x2 + 3 x molar mass of SO₄²⁻)
= 2M + 96 x 3
= 2M + 288
In 1 mol if there's 72.07% of sulphate ,
then 72.07 % corresponds to 288 g
1 % is then - 288/72.07
100 % of the compound - 288/72.07 x 100
molar mass of the compound - 399.6 g/mol
mass of 2M - 399.6 - 288 = 111.6 g
molar mass of M - 111.6 /2 = 55.8 g/mol
the element with molar mass of 55.8 is Fe.
Unknown metal is iron(III) , Fe³⁺
Answer:
<h3>In chemical reaction atoms are reactants </h3>
Answer:-
5.554 litres
Explanation:-
Initial Volume V 1 = 5.00 litres
Initial temperature T 1 = 34 C + 273 = 307 K
Final temperature T 2 = 68 C + 273 = 341 K
Using the relation of Charles Law (V 1 / T 1) = (V 2 / T 2)
New Volume V 2 = V1 x T2 / T1
Plugging in the values
V2 = 5.00 litres x 341 K / 307 K
= 5.554 litres.
