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Yanka [14]
3 years ago
10

A. amplitude B. frequency C. pitch D. speed

Chemistry
2 answers:
Darina [25.2K]3 years ago
8 0
^^ What is the question??
Liono4ka [1.6K]3 years ago
6 0
What is the question!
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a swimming pool is 50 meters long. each day a swimmer swam total of 75 lengths of the pool for practice. how many kilometers did
Brilliant_brown [7]
50x75=3750 -- metres per day
3750x15=56250 -- metres in 15 days

Divide by 1000 to convert to km
56.250km
<u>56.25km</u>
8 0
3 years ago
The balanced equation for combustion in an acetylene torch is shown below:
vichka [17]

Answer:

70mol

Explanation:

The equation of the reaction is given as:

                  2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

Given parameters:

Number of moles of acetylene = 35.0mol

Number of moles of oxygen in the tank = 84.0mol

Unknown:

Number of moles of CO₂ produced = 35.0mol

Solution:

From the information given about the reaction, we know that the reactant that limits this combustion process is acetylene. Oxygen is given in excess and we don't know the number of moles of this gas that was used up. We know for sure that all the moles of acetylene provided was used to furnish the burning procedure.

To determine the number of moles of CO₂ produced, we use the stoichiometric relationship between the known acetylene and the CO₂ produced from the balanced chemical equation:

From the equation:

         2 moles of acetylene produced 4 moles of CO₂

          ∴ 35.0 mol of acetylene would produced:  

                               \frac{35 x 4}{2} = 70mol

6 0
3 years ago
Read 2 more answers
What are the answers for this question<br> Don't just answer for points
Kisachek [45]

Answer:

i cant see it very much i dont think no one can

Explanation:

5 0
3 years ago
Read 2 more answers
How did Bohr describe the arrangement of particles within an atom?
alexandr1967 [171]

Answer: A

Explanation: Protons and neutrons form the nucleus of the atom, with electrons orbiting it.

4 0
3 years ago
Read 2 more answers
the combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110kg of carbon dioxide what is the limittin
mote1985 [20]

Answer:

Propane

Explanation:

From the question given, we were told that 0.1240 kg of propane reacted with excess oxygen to produce 0.3110kg of carbon dioxide.

Since the reaction took place in the presence of excess oxygen, therefore, propane is the limiting reactant as all of it is used up in the presence of excess oxygen.

4 0
3 years ago
Read 2 more answers
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