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astra-53 [7]
2 years ago
9

How many grams Kl are needed to prepare 100.mL of 0.55M solution?​

Chemistry
1 answer:
Makovka662 [10]2 years ago
7 0

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

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