Using a box covered with graph paper allows you to simulate which aspect of a car crash?

During a laboratory experiment, the temperature of the gas in a balloon is varied and the

lys-0071 [83]

A. The IV is the temperature of gas in the balloon.

B. The DV is the volume of the balloon.

This is because the temperature of the gas is the variable being manipulated in the experiment (Independent) and the volume is changing based on the shifts of the temperature (thus volume is Dependent).

4 0

3 years ago

Problem 1. Cylinders and a pendulum A uniform solid cylinder of radius r and mass m can roll inside a hollow cylinder of radius

Nataliya [291]

Answer:

The two answers are in the explanation

Explanation:

Please find the attached files for the solution

7 0

4 years ago

The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron

FrozenT [24]

Answer:

Speed of the electron is 2.46 x 10^8 m/s

Explanation:

momentum of the electron before relativistic effect = $M_{0} V$

where $M_{0}$ is the rest mass of the electron

V is the velocity of the electron.

under relativistic effect, the mass increases.

under relativistic effect, the new mass M will be

M = $M_{0}/ \sqrt{1 - \beta ^{2} }$

where

$\beta = V/c$

c is the speed of light = 3 x 10^8 m/s

V is the speed with which the electron travels.

The new momentum will therefore be

==> $M_{0}V/ \sqrt{1 - \beta ^{2} }$

It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have

1.75 $M_{0} V$ = $M_{0}V/ \sqrt{1 - \beta ^{2} }$

the equation reduces to

1.75 = $1/ \sqrt{1 - \beta ^{2} }$

square both sides of the equation, we have

3.0625 = 1/ $(1 - \beta ^{2} )$

3.0625 - 3.0625 $\beta ^{2}$ = 1

2.0625 = 3.0625 $\beta ^{2}$

$\beta ^{2}$ = 0.67

β = 0.819

substitute for $\beta = V/c$

V/c = 0.819

V = c x 0.819

V = 3 x 10^8 x 0.819 = 2.46 x 10^8 m/s

6 0

4 years ago

A horizontal force pushes a 26 kg sled along a driveway for a distance of 36 m. If the coefficient of sliding friction is 0.2, w

SVETLANKA909090 [29]

Answer:1834.56 joules

Explanation:

Distance=36m

Coefficient of friction=0.2

Mass=26kg

Acceleration due to gravity=9.8m/s^2

Reaction=mass x acceleration due to gravity

Reaction=26 x 9.8

Reaction=254.8N

Coefficient of friction=frictional force ➗ reaction

0.2=frictional force ➗ 254.8

Frictional force=0.2 x 254.8

Frictional force=50.96N

work=friction force x distance

Work=50.96 x 36

Work=1834.56

Work=1834.56 joules

8 0

4 years ago

A single strain gage has a nominal resistance of 120 ohm. For a quarter bridge with 120 ohm fixed resistors, strain gauge factor

natita [175]

Answer:

Output voltage is 1.507 mV

Solution:

As per the question:

Nominal resistance, R = $120\Omega$

Fixed resistance, R = $120\Omega$

Gauge Factor, G.F = 2.01

Supply Voltage, $V_{s} = 3\ V$

Strain, $\epsilon = 1000\times 10^{-6}\ strain$

Now,

To calculate the output voltage, $V_{o}$ :

WE know that strain is given by:

$\epsilon = \frac{(R + R')^{2}V_{o}}{RR'V_{s}\times G.F}$

Thus

$V_{o} = \frac{RR'V_{s}\epsilon \times G.F}{(R + R')^{2}}$

Now, substituting the suitable values in the above eqn:

$V_{o} = \frac{120\times 120\times 3\times 1000\times 10^{-6}\times 2.01}{(120 + 120)^{2}}$

$V_{o} = 1.507\ mV$

6 0

4 years ago