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2 years ago

Esmeralda Hasn't backed it in the shape of the screw is side of the magnet to 3 inches on what is the perimeter of her magnet

Mathematics

1 answer:

Vinvika [58]2 years ago

7 0

Answer:

12 INCHES

Step-by-step explanation:

Esmeralda has as magnet in the shape of a square each side is 3 inches long what is the perimeter?

A square is a quadrilateral with four equal sides.

Characteristics of a square includes:

• The diagonals bisect each other at 90°.

• Opposite sides parallel and of equal length

• The four angles of a square are equal.

perimeter of a square = 4 x length

4 x 3 = 12 inches

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Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

2 years ago

Negative 6 equal 2/9 x

Roman55 [17]

Step-by-step explanation:

-6 = 2/9 x

2/9x = -6

x = (-6)×9/2

= -27

4 0

2 years ago

The diameter of a circle is 10 in. Find its area in terms of pi

elena55 [62]

Answer:

25 pi

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

It's 12 points of u get this right<br>

earnstyle [38]

Answer:

y = -2x + 8

Step-by-step explanation:

When two points are given, the equation of the line passing through the points is given by:

$\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}$

where: $(x_1,y_1)$ and $(x_2,y_2)$ are the two points passing through the line.

Here, $(x_1,y_1) = (2,4)$ and $(x_2, y_2) = (3,2)$ .

Substituting in the formula, we have:

$\frac{y - 4}{2 - 4} = \frac{x - 2}{3 - 2}$

⇒ $\frac{y - 4}{-2} = \frac{x - 2}{1}$

⇒ y - 4 = -2x + 4

⇒ y = -2x + 8 is the required equation of the line.

4 0

2 years ago

Is this the correct answer?

charle [14.2K]

Yes, it is right... you correctly distributed the negative, and combined like terms... great job!

6 0

2 years ago