1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zepelin [54]
2 years ago
7

I NEED HELP WITH THIS CHEMISTRY QUESTION PLS

Chemistry
1 answer:
Tatiana [17]2 years ago
5 0

Answer:

Iron, according to:

2Al(s)+3Fe(NO_3)_2(aq)\rightarrow 3Fe(s)+2Al(NO_3)_3(aq)

Explanation:

Hi there!

In this case, according to the law of conservation of mass, which states that matter cannot be neither created nor destroyed, it is possible for us to figure out the missing element in the reaction by taking into account this is a single displacement reaction in which Al goes with NO3 to produce the Al(NO3)3, and therefore the other element would be iron (Fe) as can be seen on the following chemical reaction:

2Al(s)+3Fe(NO_3)_2(aq)\rightarrow 3Fe(s)+2Al(NO_3)_3(aq)

Best regards!

You might be interested in
What type of reaction is shown below?
Lemur [1.5K]
<span>What type of reaction is shown below? 

2H2O2 → 2H2O + O2

A. synthesis
B. decomposition
C. combustion</span>decomposition

answer is B
8 0
3 years ago
Read 2 more answers
Please help meee! Chemistry!
Leya [2.2K]

P=18000000/6 zeros. not sure how to do rest

6 0
3 years ago
Read 2 more answers
What color does blue and cyan pigment make?
Fed [463]

Answer:

Teal

Explanation:

Blue lightens the cyan.

3 0
3 years ago
Read 2 more answers
Calculate the standard reaction Gibbs free energy for the following cell reactions: (a) 2 Ce41(aq) 1 3 I2(aq) S 2 Ce31(aq) 1 I32
Law Incorporation [45]

<u>Answer:</u>

<u>For a:</u> The standard Gibbs free energy of the reaction is -347.4 kJ

<u>For b:</u> The standard Gibbs free energy of the reaction is 746.91 kJ

<u>Explanation:</u>

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}           ............(1)

  • <u>For a:</u>

The given chemical equation follows:

2Ce^{4+}(aq.)+3I^{-}(aq.)\rightarrow 2Ce^{3+}(aq.)+I_3^-(aq.)

<u>Oxidation half reaction:</u>   Ce^{4+}(aq.)\rightarrow Ce^{3+}(aq.)+e^-       ( × 2)

<u>Reduction half reaction:</u>   3I^_(aq.)+2e^-\rightarrow I_3^-(aq.)

We are given:

n=2\\E^o_{cell}=+1.08V\\F=96500

Putting values in equation 1, we get:

\Delta G^o=-2\times 96500\times (+1.80)=-347,400J=-347.4kJ

Hence, the standard Gibbs free energy of the reaction is -347.4 kJ

  • <u>For b:</u>

The given chemical equation follows:

6Fe^{3+}(aq.)+2Cr^{3+}+7H_2O(l)(aq.)\rightarrow 6Fe^{2+}(aq.)+Cr_2O_7^{2-}(aq.)+14H^+(aq.)

<u>Oxidation half reaction:</u>   Fe^{3+}(aq.)\rightarrow Fe^{2+}(aq.)+e^-       ( × 6)

<u>Reduction half reaction:</u>   2Cr^{2+}(aq.)+7H_2O(l)+6e^-\rightarrow Cr_2O_7^{2-}(aq.)+14H^+(aq.)

We are given:

n=6\\E^o_{cell}=-1.29V\\F=96500

Putting values in equation 1, we get:

\Delta G^o=-6\times 96500\times (-1.29)=746,910J=746.91kJ

Hence, the standard Gibbs free energy of the reaction is 746.91 kJ

7 0
3 years ago
How much water would need to be added to 1092 mL of a 54.7 M NaCl solution to make a 0.25 M solution?
babunello [35]

Answer:

237.8L of water would need to be added.

Explanation:

The first thing to do is to identify that the equation to be used is M1V1=M2V2. (This equation works because it turns everything into moles which can then be compared).

Then figure out what information you have and what is being found. In this case:

M1 = 54.7 M

V1 = 1092 mL = 1.092 L

M2 = 0.25 M

V2 = unknown

Then solve the equation for whatever you are trying to find.

M1V1=M2V2

V2=M1V1/M2

Now you need to plug everything in.

V2=(54.7M*1.091L)/0.25M

V2=238.93L

That means that the solution needs a volume of 238.7L to gain a molarity of 0.25M but the starting solution already had a volume of 1.092 L meaning that to find the amount of solvent that needs to be added you just subtract the starting volume by the volume that the solution needs to be.

238.93L - 1.091L = 237.8L

Therefore the answer is that 237.8L needs to be added to a 1.092L 54.7M NaCl solution to make the concentration 0.25M.

I hope this helps.  Let me know if anything is unclear.

8 0
2 years ago
Other questions:
  • In a 200 cm3 container, a certain amount of O2 gas is held with a piston at equilibrium with the external pressure being 1 bar.
    5·1 answer
  • Maple syrup, which comes from the sap of maple trees, contains water and natural sugars. It's a clear, brown liquid and the suga
    6·2 answers
  • Please help! Will give brainliest!!!!!!
    11·1 answer
  • Answer for this question
    13·1 answer
  • Identify the missing coefficient in the balanced equation and classify the type of reaction. Al2(CO3)3 ⟶ Al2O3 + ___CO2
    5·2 answers
  • Equilateral triangle<br> What’s the answer
    14·2 answers
  • Which food type will show no colour charge when it is tested with millon's reagent /Bluret solution​
    7·1 answer
  • If the concentration of a KCl solution is 16.0% (m/v), then the mass of KCl in 26.0 mL of solution is ________.
    11·1 answer
  • ((Write any one principle of Permaculture.​
    14·1 answer
  • 6) Which of the following does not fall in the biotic component of the ecosystem?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!