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3 years ago

Can anyone tell me whether N2 bonds or Cl2 bonds are stronger? Thanks!

Chemistry

1 answer:

Nadusha1986 [10]3 years ago

6 0

Answer:

Cl2 bonds are stronger!!!!!

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What are the n, l, and possible ml values for the 2p and 5f sublevels?

elixir [45]

Answer:

1. 2p sublevels, n = 2, orbital p, l = 1, ml = 0, ±1

2. 5f sublevels n = 5, orbital f, l = 3, ml = 0, ±1, ±2, ±3

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Subshell number, 0 ≤ l ≤ n − 1

3. Orbital energy shift, -l ≤ ml ≤ l

4. Spin, either -1/2 or +1/2

So,

1. 2p sublevels,

n = 2, orbital p, so l = 1, ml = 0, ±1

2. 5f sublevels

n = 5, orbital f, so l = 3, ml = 0, ±1, ±2, ±3

7 0

3 years ago

2. Calculate the pl of the following amino acids(use their Pka values) a. Arginine b. Glutamic acid of water an c. Asparagine d.

Savatey [412]

<h2>♨ANSWER♥</h2>

pl (25*C)

Arginine -----> 10.76

Glutamic -----> 3.08

Asparagine -----> 5.43

Tyrosine -----> 5.63

☆...hope this helps...☆

_♡_mashi_♡_

5 0

2 years ago

From the amount of NaOH added at the 1st equivalence point, calculate the original molarity of the acid. Carry out the same calc

gizmo_the_mogwai [7]

Answer:

Molarity of acid, Ca = Cb*Vb*A/Va*B

Explanation:

Using H2SO4 as acid, the reaction is as follow:

2NaOH + H2SO4 ⇒ Na2SO4 + 2H2O

Volume of acid = Va; Volume of base = Vb, Molar concentration of acid = Ca; Molar concentration of base = Cb; Molarity of acid = A and Molarity of base = B

Ca*Va/Cb*Vb =A/B

∴ Ca = Cb*Vb*A/Va*B

4 0

3 years ago

Codeine C18H21NO3 is a weak organic base. A 5.0 x 10^-3 M solution of codeine has a pH of 9.95. Calculate the value of Kb for th

arsen [322]

Answer:

Kb = $4.45\times10^{-7}\ mol/L$

$p^{Kb}=6.35$

Explanation:

For a weak organic base, the formula to find $p^{OH}$ is given by:

$p^{OH}=p^{K_b}+\log c$

where c is the concentration of base.

Here c= $5\times10^{-3}\ M$

$p^{H}=9.95\\p^{OH}=14-p^{H}=14-9.95=4.05$

Substituting the above values in the formula,we get:

$p^{k_b}=p^{OH}-\log c\\p^{k_b}=4.05-\log (5\times10^{-3})\\p^{K_b}=6.35\\K_b=$antilog 6.35=4.45\times10^{-7}\ mol/L$

Hence:

Kb = $4.45\times10^{-7}\ mol/L$

$p^{Kb}=6.35$

7 0

3 years ago

There is a meme in the image i have what does it mean

Gelneren [198K]

Answer:

The 4s2 is preventing 3d10 from following 1s2 2s2 2p6 3s2 3p6.

Explanation:

the meme is quite common.

5 0

3 years ago

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