The force on an object use Socratic glad to help ..
Answer:
The temperature after half an hour is 
Solution:
As per the question;
Metabolic rate of the person is 3.0105 J/h
Temperature, T = 
Mass of the water, 
Time duration, t = 0.5 h = 30 min = 180 s
Now,
Heat, 
Thus heat transfer in half an hour:

Now, the temperature of water after half an hour, T' is given by:

where
s = 4186 J


Answer:
The sum of momenta of each object before and after collision is equal . Thus when they collide , their momentum will change but its sum will be sane as the sum of the momentum before collision
Answer:
5080.86m
Explanation:
We will divide the problem in parts 1 and 2, and write the equation of accelerated motion with those numbers, taking the upwards direction as positive. For the first part, we have:


We must consider that it's launched from the ground (
) and from rest (
), with an upwards acceleration
that lasts a time t=9.7s.
We calculate then the height achieved in part 1:

And the velocity achieved in part 1:

We do the same for part 2, but now we must consider that the initial height is the one achieved in part 1 (
) and its initial velocity is the one achieved in part 1 (
), now in free fall, which means with a downwards acceleration
. For the data we have it's faster to use the formula
, where d will be the displacement, or difference between maximum height and starting height of part 2, and the final velocity at maximum height we know must be 0m/s, so we have:

Then, to get
, we do:



And we substitute the values:

It is transferred by direct contact, say you touched it, you would feel the heat