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3 years ago

(b) What property do all elements in the same column of the Periodic Table as

Chemistry

2 answers:

olga55 [171]3 years ago

8 0

This is the answer of your question .☺☺

Shalnov [3]3 years ago

7 0

Well the group fluorine is in is known as Halogens. Halogens all have seven valence electrons in their outer shell. They exist as diatomic molecules. Furthermore they readily combine with metals to form salts

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The compound CaSO4 ionizes into a calcium ion and a sulfate ion (SO4). Calcium has two electrons in its outer shell. Upon ioniza

gtnhenbr [62]

Answer:

-2

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or $1s^22s^22p^63s^23p^64s^2$

There are 2 valence electrons of Calcium.

Thus, calcium loses two electrons to sulfate ion and sulfate ion accepts these electrons to form ionic bond.

Calcium sulfate, $CaSO_4$ is formed when 2 valence electrons of calcium are loosed and they are gained by sulfate ion.

$Ca^{2+}+SO_4^{2-}\rightarrow CaSO_4$

Thus, the charge on the sulfate ion is -2.

6 0

3 years ago

S-->SO2-->SO3-->H2SO4-->SO2-->H2SO3-->Na2SO3-->SO2--> Na2SO3-->Na2SO4-->BaSO4

siniylev [52]

That is not a question/problem and makes no sense whatsoever

4 0

3 years ago

When the pressure of a gas doubles, the new volume

s344n2d4d5 [400]

Answer:

yes it does

Explanation:

6 0

3 years ago

You wish to make a 0.299 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid

Art [367]

Answer:

$V_1=2.49mL$

Explanation:

Hello,

In this case, considering that the moles of hydrioiodic acid remain unchanged during the dilution process:

$n_{HI}=n_{HI}$

One could apply the following equality in terms of molarity:

$V_1M_1=V_2M_2$

Whereas the subscript 1 accounts for the solution before the dilution and 2 after the dilution, therefore, the required volume of 6.00 M acid is:

$V_1=\frac{V_2M_2}{M_1} =\frac{50.0mL*0.299M}{6.00M}=2.49mL$

Best regards.

5 0

3 years ago

What is the volume in liters of 321 g of liquid with a density of 0.84 g/mL

Rasek [7]

Density is weight by volume.

First. If you divide the weight by density you can find the volume

Second you must convert the ML in to Liters.

$\frac{321 \frac{g}{1}}{0.84 \frac{g}{mL}} = \frac{321(g)(mL)}{0.84g}=\frac{321mL}{0.84}=382.14mL$

1L=1000ml

$\frac{1L}{1000mL}$

$(382.14mL)( \frac{1L}{1000mL})= \frac{(382.14mL)(L)}{1000mL} =\frac{382.14L}{1000}=0.38214L$

0.38214 Liters.

4 0

3 years ago