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RoseWind [281]
3 years ago
6

(b) What property do all elements in the same column of the Periodic Table as

Chemistry
2 answers:
olga55 [171]3 years ago
8 0

This is the answer of your question .☺☺

Shalnov [3]3 years ago
7 0
Well the group fluorine is in is known as Halogens. Halogens all have seven valence electrons in their outer shell. They exist as diatomic molecules. Furthermore they readily combine with metals to form salts
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How much heat energy, in kilojoules, is required to convert 72.0 gg of ice at −−18.0 ∘C∘C to water at 25.0 ∘C∘C ? Express your a
Ghella [55]

Answer: The enthalpy change is 34.3 kJ

Explanation:

The conversions involved in this process are :

(1):H_2O(s)(-18^0C)\rightarrow H_2O(s)(0^0C)\\\\(2):H_2O(s)(0^0C)\rightarrow H_2O(l)(0^0C)\\\\(3):H_2O(l)(0^0C)\rightarrow H_2O(l)(25^0C)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{l}\times (T_{final}-T_{initial})]

where,

\Delta H = enthalpy change = ?

m = mass of water = 72.0  g

c_{s} = specific heat of ice = 2.09J/g^0C

c_{l} = specific heat of liquid water = 4.184J/g^0C

n = number of moles of water = \frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{72.0g}{18g/mole}=4.00moles

\Delta H_{fusion} = enthalpy change for fusion = 6010 J/mole

Now put all the given values in the above expression, we get

\Delta H=[72.0g\times 2.09J/g^0C\times (0-(-18)^0C]+4.00mole\times 6010J/mole+[72.0g\times 4.184J/g^)C\times (25-0)^0C]\Delta H=34279.8J=34.3kJ        (1 KJ = 1000 J)

Therefore, the enthalpy change is 34.3 kJ

5 0
3 years ago
Tommy was walking at a rate of 4
Helga [31]
A positive acceleration indicates that the object sped up. This means that if you compare the first speed to the second, the second speed should be higher. 

A negative acceleration indicates that the object has slowed down. This means that if you compare the first speed to the second, the second speed should be lower.

If an acceleration is 0, it means that it neither slowed down nor sped up.

Now let us analyze your problem by listing down the speed and the time:

At noon: 4 mi/hr 
12:30 :   6 mi/hr
2:30   :   2 mi/hr

From noon to 12:30, you will notice that there is an increase in speed. This means that Tommy had a positive acceleration. (Rules out D.)

From 12:30 to 2:30, there is a decrease in speed. This would indicate that Tommy had a negative acceleration. (Rules out C.) 

No speed was the same, so acceleration was never 0. (Rules out A.)

From the assumptions above, we can now deduce that the answer is B.


8 0
3 years ago
I went to the doctor for a check-up last week. First, she examined the (1) ___ portion of my body by listening to my heart and t
Zinaida [17]
1. medial
2.superior
3. inferior
4.lateral
5.inferior
7 0
3 years ago
Which of the following has no electrons? Use a periodic table. Question 1 options: He 2+ He H– H
UkoKoshka [18]

do you have anymore numbers to add to this problem??


7 0
3 years ago
WHAT TIME IS IT WHERE U ARE?
Svetllana [295]

Answer:

3:46 pm

Explanation:

7 0
2 years ago
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