In the oxidation of iron; how many grams of iron (III) oxide will be produced from 6.20 mol of Fe?
1 answer:
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86.66 % by weight of ascorbic acid in the tablet, when 0. 1220 g vitamin c tablet was dissolved in acid. This required 11. 50 ml of 0. 01740 m to reach the endpoint.
A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.
→
So, the balanced chemical equation for the reaction will be:
→
That means, 3 mol of of ascorbic acid reacts with 1 mol of
Moles of available is 0.0174 X 0.0115 =0.0002001 mol
Moles of ascorbic acid to be yielded should be 3 X 0.0002001 =0.0006003
So, percent mass of ascorbic acid in the tablet will be:
(0.1057 / 0.1220) X 100 %
=86.66 %
Hence, the third option is the correct answer.
Learn more about balanced chemical equations here:
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PH is defined as the negative log of Hydronium Ion concentration.
So, in order to find the pH of vinegar, we find the negative log of its hydronium ion concentration.
![pH=-log[ H_{3}O^{+}] \\ \\ pH=-log(1.6 * 10^{-3}) \\ \\ pH=2.8](https://tex.z-dn.net/?f=pH%3D-log%5B%20H_%7B3%7DO%5E%7B%2B%7D%5D%20%5C%5C%20%20%5C%5C%20%0ApH%3D-log%281.6%20%20%2A%2010%5E%7B-3%7D%29%20%20%5C%5C%20%20%5C%5C%20%0ApH%3D2.8)
So, the pH of given vinegar solution will be 2.8.
Therefore, the answer to this question is option B
So, in order to find the pH of vinegar, we find the negative log of its hydronium ion concentration.
So, the pH of given vinegar solution will be 2.8.
Therefore, the answer to this question is option B
Answer:
Value of equilibrium constant is 0.0888
Explanation:
Both and
are gaseous. Hence equilibrium constant depends upon partial pressures of
and
.
Initially no and
were present.
Hence mole fraction of and
at equilibrium can be calculated from coefficient of
and
in balanced equation.
Mole fraction of = (number of moles of
)/(total number of moles of
and
) =
Mole fraction of = (number of moles of
)/(total number of moles of
and
) =
Let's assume both and
behaves ideally.
Therefore partial pressure of ,
and P_{CO_{2}}= x_{CO_{2}}.P_{total}
Where x represents mole fraction
So,
So,