All categories

3 years ago

Whats an organic chemist

Chemistry

1 answer:

olga2289 [7]3 years ago

7 0

They study the structure, properties, and reactions of molecules that contain carbon

You might be interested in

Balance this equation. Not all spots have to have a number.

Lisa [10]

2Na+2H2O----2NaOH+H2

3 0

3 years ago

A water bottle has a mass of 14.0g. Given a density of 1.38g/cm^3, what is the volume of the plastic used to make the water bott

Kipish [7]

Answer:

$\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}$

Given:

Mass = 14.0 g

Density ( $\rho$ ) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

$\boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}$

Substituting value of m & density in the formula:

$\sf \implies 1.38 = \frac{14.0}{V} \\ \\ \sf \implies V = \frac{14.0}{1.38} \\ \\ \sf \implies V = 10.14 \ cm^3$

$\therefore$

Volume of the plastic used to make water bottle = 10.14 cm³

6 0

3 years ago

For the following reaction, 5.04 grams of nitrogen gas are allowed to react with 8.98 grams of oxygen gas: nitrogen(g) + oxygen(

OLga [1]

Answer:

1. 10.8 g of NO

2. N₂ is the limting reagent

3. 3.2 g of O₂ does not react

Explanation:

We determine the reaction: N₂(g) + O₂(g) → 2NO(g)

We need to determine the limiting reactant, but first we need the moles of each:

5.04 g / 29 g/mol = 0.180 moles N₂

8.98 g / 32 g/mol = 0.280 moles O₂

Ratio is 1:1, so the limiting reactant is the N₂. For 0.280 moles of O₂ I need the same amount, but I only have 0.180 moles of N₂

Ratio is 1:2. 1 mol of N₂ can produce 2 moles of NO

Then, 0.180 moles of N₂ may produce (0.180 .2) / 1 = 0.360 moles NO

If we convert them to mass → 0.360 mol . 30 g/1 mol = 10.8 g

As ratio is 1:1, for 0.180 moles of N₂, I need 0.180 moles of O₂.

As I have 0.280 moles of O₂, (0.280 - 0.180 ) = 0.100 moles does not react.

0.1 moles . 32 g/mol = 3.2 g of O₂ remains after the reaction is complete.

8 0

3 years ago

Read 2 more answers

What state of matter in which particles are arranged in either a crystalline or an amorphous form

Ainat [17]

Idk to explain this but the answer is Solid...i think...

8 0

3 years ago

Which reactants would lead to a spontaneous reaction?

balandron [24]

Answer: Option (b) is the correct answer.

Explanation:

The elements which have excess or deficiency of electrons will react readily.

Atomic number of Mn is 25 and electronic configuration of $Mn^{2+}$ is [Ar] $4s^{0}3d^{5}$ . This configuration is stable.

Atomic number of Cr is 24 and electronic configuration of $Cr$ is [Ar] $4s^{1}3d^{5}$ . This configuration is not stable.

Atomic number of Fe is 26 and electronic configuration of $Fe$ is [Ar] $4s^{2}3d^{6}$ . This configuration is stable.

Atomic number of Cu is 29 and electronic configuration of $Cu^{2+}$ is [Ar] $4s^{0}3d^{9}$ . This configuration is not stable.

Atomic number of Al is 13 and electronic configuration of Al is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$ . This configuration is not stable.

Atomic number of Ba is 56 and electronic configuration of $Ba^{2+}$ is [Kr] $4d^{10}5s^{2}5p^{6}$ . This configuration is stable.

Atomic number of Mg is 12 and electronic configuration of $Mg^{2+}$ is $1s^{2}2s^{2}2p^{6}$ . This configuration is stable.

Atomic number of Sn is 50 and electronic configuration of Sn is [Kr] $4d^{10}5s^{2}5p^{2}$ . This configuration is stable.

Thus, we can conclude that out of the given options, only Fe and $Cu^{2+}$ reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.

8 0

3 years ago