A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. ... A rock is an aggregate of one or more minerals, or a body of undifferentiated mineral matter.
Answer:
120 moles of NO
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4NH₃ + 6NO —> 5N₂ + 6H₂O
From the balanced equation above,
6 moles of NO reacted to produce 5 moles of N₂.
Finally, we shall determine the number of mole NO needed to produce 100 moles of N₂. This can be obtained as follow:
From the balanced equation above,
6 moles of NO reacted to produce 5 moles of N₂.
Therefore, Xmol of NO will react to produce 100 moles of N₂ i.e
Xmol of NO = (6 × 100)/5
Xmol of NO = 120 moles
Therefore, 120 moles of NO is needed for the reaction.
Answer:
NaHCO 3 ( s ) + HC 2 H 3 O 2 ( aq ) ⟶NaHC2H3O2 + H2CO3 → H2O + CO2
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2
Explanation:
Sodium bicarbonate and acetic acid reacts to form Sodium acetate and carbonic acid. The carbonic acid then produce carbon dioxide gas and water after undergoing decomposition.
Answer:
15.2 grams of calcium chloride are produced and HCl is the limiting reactant.
Explanation:
Hello there!
In this case, according to the described scenario, it is possible to realize that the reaction between hydrochloric acid and calcium hydroxide is:
Whereas there is a 2:1 mole ratio of the acid to the base. In such a way, with the given masses, we can compute how much calcium chloride product is produced due to the chemical reaction via stoichiometry:
Whereas we infer that the correct amount is 15.2 g since HCl is the limiting reactant as it produces the fewest grams of the desired product. Consequently, the calcium hydroxide is the excess reactant here.
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Answer:
6.576 g NaCl
Explanation:
2Na + Cl2 --> 2 NaCl
Step 1: Find out moles of Na and Cl to determine the limiting reactant:
moles Na = 12/23 = 0.52 moles Na
moles Cl2 = 16/71=0.225 moles Cl2
ratio Na:Cl is 2.3:1 so Cl is the limiting reactant.
Step 2: How many moles of NaCl are formed:
moles NaCl = moles Cl2 x (1 mol NaCl/2 moles Cl2) = 0.225/2 = 0.1125 moles NaCl
Step 3:
mass NaCl = moles NaCl x MM NaCl = 0.1125 x 58.45 = 6.576 g NaCl
