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3 years ago

What is the mole fraction of NaCl if you have 5.3 moles of KCL, 2.3 moles of NaCl and 4.6 moles of NaOH? PLZ HELP!!!!

Chemistry

1 answer:

DENIUS [597]3 years ago

3 0

Answer:

The mole fraction of NaCl is 0.1885

Explanation:

We are given;

Moles of NaCl = 2.3 moles
Moles of KCl = 5.3 moles
Moles of NaOH = 4.6 moles

We are required to calculate the mole fraction of NaCl

Mole fraction will be given by getting a ratio of moles of NaCl to the total number of moles.

In this case;

The total number of moles = 2.3 moles + 5.3 moles + 4.6 moles

= 12.2 moles

Therefore;

Mole fraction of NaCl = 2.3 moles ÷ 12.2 moles

= 0.1885

Hence, the mole fraction of NaCl is 0.1885

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mario62 [17]

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3 years ago

Which reaction will occur? 2NaBr I2 Right arrow. 2NaI Br2 2Fe Al2O3 Right arrow. 2Al Fe2O3 2AgNO3 Ni Right arrow. Ni(NO3)2 2Ag P

Likurg_2 [28]

The reaction that has been occurred will be $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$ .

The chemical reaction has been defined as the interaction of the reactant molecules for the formation of the product. The changes have been taken place in the reactivity series and under specific conditions.

<h3>Reaction occur</h3>

The displacement reaction has been taken place based on the reactivity series. The more reactive element has been able to displace the less reactive element in the compound and form a new compound.

The following reactions have been analyzed as:

$\rm 2\;NaBr\;+\;I_2\;\rightarrow\;2\;NaI\;+\;Br_2$

In the reaction, Br has been replaced by Iodine. The iodine has been less reactive than Br and thus will not form the compound.

Thus, this reaction will not occur.

$\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$

In the reaction, Al has been replaced by Fe. The Fe is more reactive than Al. thus this reaction will occur.

$\rm 2\;AgNO_3\;+\;Ni\;\rightarrow\;Ni(NO_3)_2\;+\;2\;Ag$

The nickel has been less reactive than Ag, and thus will not be able to form the product.

Thus, this reaction will not occur.

$\rm Pb\;+\;Zn(C_2H_3O_2)_2\;\rightarrow\;Zn\;+\;Pb(C_2H_3O_2)_2$

The lead has been less reactive than Zn, and thus will not be able to form the product.

Thus, this reaction will not occur.

The reaction that has been occurred will be $\rm 2\;Fe\;+\;Al_2O_3\;\rightarrow\;2\;Al\;+\;Fe_2O_3$ .

Learn more about reactivity series, here:

brainly.com/question/10443908

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3 years ago

The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table b

denis-greek [22]

Answer:

220.42098 amu

Explanation:

(220 .9 X .7422) + (220 X .0.1278) + (218.1 X 0.13) = 220.42098 amu

These are weighted averages.

So, we will take mass of one and multiply by abundance percentage that is provided and add them together.

In order to calculate the average atomic mass, we have to convert the percentages of abundance to decimals. So, you get

(220 .9 X .7422) + (220 X .0.1278) + (218.1 X 0.13) = 220.42098 amu

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3 years ago

Given the following sets of values, calculate the unknown

weqwewe [10]

Answer:

3.91 L

Explanation:

Using the ideal gas law equation as follows:

PV = nRT

Where:

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Based on the information given in this question,

P = 5.23 atm

V= ?

n = 0.831 mol

T = 27°C = 27 + 273 = 300K

Using PV = nRT

V = nRT/P

V = (0.831 × 0.0821 × 300) ÷ 5.23

V = 20.47 ÷ 5.23

V = 3.91 L

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3 years ago

Between Na and Na+ which has larger size

viva [34]

Answer:

Na+ is smaller than Na because, it has given away one electron because of which the electron shielding gets stronger due to more protons and less electrons. Whereas, Cl- is larger than Cl because it has gained an extra electron and so, the no.07‏/12‏/2010

Explanation:

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3 years ago