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grigory [225]
3 years ago
8

Please help!!!! Really need to know this!!

Chemistry
1 answer:
Scilla [17]3 years ago
7 0

The theoretical yield of NaCl : 15 mol

<h3>Further explanation</h3>

Given

15 mol Na

15 mol Cl₂

Required

The theoretical yield of NaCl

Solution

Reaction

2Na + Cl₂ ⇒ 2NaCl

A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Find limiting reactant (mol : coefficient) :

Na = 15 : 2 = 7.5

Cl₂ = 15 : 1 = 15

The limiting reactant = Na(smaller ratio)

Mol of NaCl based on mol Na as limiting reactant.

From the equation, mol ratio of Na : NaCl = 2 : 2, so mol NaCl = <u>15 mol</u>

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2 years ago
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Varvara68 [4.7K]
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3 years ago
Please help me !!!!
just olya [345]

Answer:

12, 28, 16

Explanation:

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3 years ago
8. What was the original concentration in the BHL sample, if the dilution is 1:500 and the concentration 0.07 mg/ml
Yakvenalex [24]

Answer:

The original concentration is "35 mg/ml".

Explanation:

According to the question,

The solution is diluted,

= 1:50

The initial volume,

V1 = 1 ml

Final concentration,

= 0.07 mg

then,

The final volume,

V2 = 500 ml

As we know,

⇒ V_1N_1=V_2N_2

or,

⇒ N_1=\frac{V_2N_2}{V_1}

On substituting the values, we get

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2 years ago
What is the mass of 6.78x1050 molecules of NaCl
ryzh [129]

Answer:

Explanation:

As

Molar mass of NaCl= 58.44 gm

So we got it that,

58.44 mass of NaCl contain = 6.023*10^23  molecules of Na Cl

x mass will contain = 6.78*10^50

by cross multiplication , we get

x=  58.44*(6.78*10^50)/  6.023*10^23  

x= 65.785 * 10^27  molecules

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