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bija089 [108]
4 years ago
8

Classify these structures as hemiacetal, acetal, or other.

Chemistry
2 answers:
saveliy_v [14]4 years ago
8 0
Hemiacetals are compounds that are derived from aldehydes and ketones while acetals are compounds with a central carbon atom with 4 bonds attached to it. It must be saturated and has a tetrahedral geometry.
Pepsi [2]4 years ago
6 0

Explanation:

Hello!

Let's solve this!

A hemiacetal is the product of a reaction between an aldehyde and an alcohol.

The structure is

      R

       |

RO-C-H

       |

      OH

An acetal has two alkoxy groups. The structure is :

        H

         |

 OH-C-OR '

         |

        OR ''

Of the compounds given, the first two are hemiacetals.

The next three are acetals and the last two are others.

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vlabodo [156]

Answer:

O₂ (g).

Explanation:

  • All elements that found in nature has heat of formation (Hf) equal 0 J/mol.
  • So, the substance that  has heat of formation (Hf) equal 0 J/mol is O₂ (g).
  • H₂O is formed from the reaction of hydrogen and oxygen and has Hf, Also, the solidification of H₂O (s) from H₂O (l) has (Hf).
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3 years ago
Read 2 more answers
If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution
Shtirlitz [24]

Explanation:

a) Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

where,

A = absorbance of solution = 0.945

c = concentration of solution = ?

l = length of the cell = 1.20 cm

\epsilon = molar absorptivity of this solution =5.56\times 10^4 M^{-1} cm^{-1}

0.945=5.56\times 10^4 M^{-1} cm^{-1}\times 1.20 \times c

c=1.4163\times 10^{-5} M=14.16 \mu M

(1\mu M=10^{-6} M)

14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.

b) c=1.4163\times 10^{-5} mol/L

1 L of solution contains 1.4163\times 10^{-5} moles of red dye.

Mass of 1.4163\times 10^{-5} moles of red dye:

1.4163\times 10^{-5}\times 879.86g/mol=0.01246 g

(w/v)\%=\frac{\text{Mass of solute (g)}}{\text{Volume of solvent (mL)}}\times 100

red(w/v)\%=\frac{0.01246 g}{1000 mL}\times 100=0.001246\%

c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = c=1.4163\times 10^{-5} M

Concentration of red solution after dilution = c'

c=c'\times 5

1.4163\times 10^{-5} M=c'\times 5

c'=2.83\times 10^{-6} M

The final concentration of the diluted solution is 2.83\times 10^{-6} M

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Answer:

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<h2>Explanation:</h2>

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