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3 years ago

11

How much energy is stored in a spring with a spring constant of 250 N/m if the spring is compressed a distance of 0.46 m from it

s free length?
Group of answer choices

120 J

58 J

53 J

26 J

14000 J

1 answer:

Alexxandr [17]3 years ago

7 0

F=-ks

(F=Force) (k=spring constant) (s=displacement)

F=-(250)(0.46)
F=-115N

W=Fs
W=115(0.46)
W=52.9J

W= ∆Energy
So ∆E=52.9 J

Answer: 53J (third option)

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From the question we are told that

The first wavelength is $\lambda_1 = 650 \ nm = 650 *10^{-9} \ m$

The second wavelength is $\lambda_2 = 429 \ m = 420 *10^{-9 } \ m$

The order of the fringe is $n = 2$

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$d = \frac{1}{N }$

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=> $\theta_1 = sin^{-1} [\frac{ 2 * \lambda }{d}]$

=> $\theta_1 = sin^{-1} [\frac{ 2 * 650 *10^{-9} }{ 2*10^{-6}}]$

=> $\theta_1 = 40.5 ^o$

Generally the condition for constructive interference for the second ray is mathematically represented as

$d sin(\theta_2) = n * \lambda_2$

=> $\theta_2 = sin^{-1} [\frac{ 2 * \lambda_1 }{d}]$

=> $\theta_2 = sin^{-1} [\frac{ 2 * 420 *10^{-9} }{ 2*10^{-6}}]$

=> $\theta_2 = 24.8 ^o$

Generally the angular separation is mathematically represented as

$\theta = \theta_1 - \theta_1$

=> $\theta = 42.5^o - 24.8^o$

=> $\theta = 15.7^o$

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