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kkurt [141]
2 years ago
11

1/​A current of 0.5A flows through a resistor of resistance of 20 Ω.

Physics
1 answer:
ElenaW [278]2 years ago
4 0

Answer:

20

Explanation:

from V= IR

I = 0.5A

R= 20ohm

so... Potential difference V= 0.5×20 = 10

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A high power line carries a current of 1.0 kA. What is the strength of the magnetic field this line produces at the ground, 10 m
solmaris [256]

Answer:

The strength of the magnetic field that the line produces is 2x10^{-5} Tesla.

Explanation:

From Biot-Savart law, the equation to determine the strength of the magnetic field for any straight wire can be deduced:

           

B = \frac{\mu_{0}I}{2\pi r} (1)      

                                     

Where \mu_{0} is the permiability constant, I is the current and r is the distance from the wire.    

             

Notice that it is necessary to express the current, I, from kiloampere to ampere.

I = 1.0kA \cdot \frac{1000A}{1kA} ⇒ 1000A

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B = \frac{(4\pi x10^{-7}T.m/A)(1000A)}{2\pi (10m)}    

           

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