Remark
This is a very interesting question. Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.
y = x (1)
3x + 4y = 12 (2)
Put x in for y in equation 2
3x + 4x = 12
7x = 12
x = 12/7
x = 1.714
y = 1.714
Problem A
<em><u>x intercept</u></em>
The x intercept occurs when y = 0
3x + 4(0) = 12
3x = 12 Divide by 3
x = 12/3
x = 4
the x intercept = (4,0)
<em><u>y intercept</u></em>
The y intercept occurs when x =0
3(0) + 4y = 12
4y = 12
y = 12/4
y = 3
y intercept = (0,3)
Problem B
x and y both equal 1.714 so they are also the length of the square's side.
Problem C
See solution above. x =y is the key fact.
x = y = 1.714
Answer:
45 degrees
Step-by-step explanation:
Since we have a right triangle, we use the appropriate trigonometric ratio
The angle marked P faces QR and that makes it the opposite side
PR faces the right angle and that makes it the hypotenuse
The trigonometric ratio that links the opposite and the hypotenuse is the sine
It is the ratio of the opposite to the hypotenuse
Thus;
sin P = √26/2 √13
Sin P = √2/2
P = arc sin √2/2
P = 45 degrees
Find a common multiplier between both which would be 4. then divide each term by 4. all you have left stays in the parenthesees.
4 (2x+5)
i hope it helps mark me brainliest
Step-by-step explanation:
it is Parallelogram
