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Ksenya-84 [330]
2 years ago
11

What is the initial pressure of a gas if it’s occupied a volume of 0.375 L but now occupies a volume of 1.25 L at a pressure of

95.5 K PA
Chemistry
1 answer:
MrMuchimi2 years ago
7 0

Answer:

318 kPa

Explanation:

Step 1: Given data

  • Initial pressure (P₁): ?
  • Initial volume (V₁): 0.375 L
  • Final pressure (P₂): 95.5 kPa
  • Final volume (V₂): 1.25 L

Step 2: Calculate the initial pressure of the gas

Assuming constant temperature and ideal behavior, we can calculate the initial pressure of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₁ = P₂ × V₂ / V₁

P₁ = 95.5 kPa × 1.25 L / 0.375 L = 318 kPa

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Solid iron metal reacts with solid sulfur at room temperature to produce solid iron (ll) sulfide? Express as a chemical equation
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Calculate the final Celsius temperature when 634 L at 21 °C is compressed to 307 L.
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Answer:

- 130.64°C.

Explanation:

  • We can use the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

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<em>V₁T₂ = V₂T₁</em>

<em></em>

V₁ = 634.0 L, T₁ = 21.0°C + 273 = 294.0 K.

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3 years ago
A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 234 picometers and its
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\delta=101.13 g/cm^3

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