Answer:
the equilibrium partial pressure of BrCl is pBC = 784.52 torr
Explanation:
Since
Br₂(g) + Cl₂(g) ⇌ 2BrCl(g) , Kp=1.112 at 150 K
denoting BC as BrCl , B as Br₂ , C as Cl₂, p as partial pressure , then
Kp = pBC²/[pB*pC]
solving for pBC
pBC = √(Kp*pB*pC)
replacing values
pBC = √(Kp*pB*pC) = √(1.112*751 torr*737 torr) = 784.52 torr
pBC = 784.52 torr
then the equilibrium partial pressure of BrCl is pBC = 784.52 torr
Explanation:
Mass of the organic compound = 200g
Mass of carbon = 83.884g
Mass of hydrogen = 10.486g
Mass of oxygen = 18.640g
The mass of nitrogen = mass of organic compound - (mass of carbon + mass of hydrogen + mass of oxygen)
Mass of nitrogen = 200 - (83.884 + 10.486 + 18.64) = 200 - 113.01
Mass of nitrogen = 86.99g
The empirical formula of a compound is its simplest formula.
It is derived as shown below;
C H O N
Mass 83.884 10.486 18.64 86.99
molar
mass 12 1 16 14
Moles 83.884/12 10.486/1 18.64/16 86.99/14
6.99 10.49 1.17 6.21
Divide
by
lowest 6.99/1.17 10.49/1.17 1.17/1.17 6.21/1.17
6 9 1 5
Empirical formula C₆H₉ON₅
learn more:
Empirical formula brainly.com/question/2790794
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