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Svet_ta [14]
3 years ago
8

A barrel of water weighs 60 pounds. What must you put in it for it to weigh 40 pounds?

Chemistry
2 answers:
Murljashka [212]3 years ago
6 0

A barrel of water weighs 60 pounds. What must you put in it for it to weigh 40 pounds?

A hole

astraxan [27]3 years ago
3 0

Answer:

A hole

Explanation:

put a hole in the barrel and let some water out

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f a cup of coffee is at 90°C and a person with a body temperature of 36°C touches it, how will heat flow between them?
coldgirl [10]

The heat flows between the two by the cup. The cup gives the coffee heat to the person and vise versa.

Hope this helps!

3 0
3 years ago
9) All elements can be sorted into 3 simple groups:
serious [3.7K]

Answer: B) metals, non-metals, metalloids

An example of a metal is iron. A non-metal example is oxygen, which is a gas at STP (standard temperature and pressure).

A metalloid is a bit of a mix between a metal and non-metal element. It's sorta like an element that has both properties of metals and non-metals, or it's in a murky gray area. An example of a metalloid would be silicon.

6 0
2 years ago
Read 2 more answers
How many grams of sodium nitrate (NaNO2) will dissolve in 100g of water at 20°C?​
inn [45]
88g ( so sorry if this isn’t correct )
8 0
3 years ago
To determine the absolute age of rocks and fossils, geologists use _____.
Pavlova-9 [17]

Answer:

The rates of decay of radioactive elements

Explanation:

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7 0
3 years ago
Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
galben [10]

The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

PV = nRT

1.5 × 12 = n × 0.0821 × 280

18 = n × 22.988

Divide both side by 22.988

n = 18 / 22.988

n = 0.783 mole

Next, we shall determine the mole of NaCl needed for the reaction.

F₂ + 2NaCl —> Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.

Finally, we shall determine the mass of 1.566 moles of NaCl.

  • Mole = 1.566 moles
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

6 0
2 years ago
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