Answer:
<h2>
<em>−2.832</em></h2>
I hope this helps you! :)
Answer:
See below, please!
Step-by-step explanation:
We can set up a system of equations to model this problem. Let's consider the student's ticket as x, and y for the adult ticket.
So since the student ticket is $1.50, and adult is $4, we can set up the following equation:
, since they collected $5050 total.
We can set up another equation modeling the number of people who came to the game. This would be x+y=2200.
Solve this, and we get x= 1500 and y=700. So, they sold 1500 student tickets and 700 adult tickets.
Hope this helped!
Answer:
Maximum area = 800 square feet.
Step-by-step explanation:
In the figure attached,
Rectangle is showing width = x ft and the side towards garage is not to be fenced.
Length of the fence has been given as 80 ft.
Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced
80 = x + x + y
80 = 2x + y
y = (80 - 2x)
Now area of the rectangle A = xy
Or function that represents the area of the rectangle is,
A(x) = x(80 - 2x)
A(x) = 80x - 2x²
To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.

= 80 - 4x
A'(x) = 80 - 4x = 0
4x = 80
x = 
x = 20
Therefore, for x = 20 ft area of the rectangular patio will be maximum.
A(20) = 80×(20) - 2×(20)²
= 1600 - 800
= 800 square feet
Maximum area of the patio is 800 square feet.
Use A: to find the value of x. In order to find that you would have to match one part of the proportion. x should be the numerator over 15 and 12 should be over 20 (The total length of that side of the triangle). Good luck. : )
Answer:

Step-by-step explanation:
