The nucleus!! This is made up of protons and neutrons that each weigh about 1 amu.
Electrons are not found in the nucleus and weigh almost nothing so chemistry in school doesn’t bother with them :)
n=20 mol
(NH)4 SO4
Atomic masses :
N- 14
H- 1
S- 32
O- 16
Therefore M= 14×2 + 1×8 + 32 + 16×4
= 132
m= nM
= 20×132
= 2640g
Answer:
1.3×10⁻³ M
Explanation:
Hello,
In this case, given the dissociation reaction of acetic acid:
![CH_3CO_2H(aq) + H_2O(l) \rightleftharpoons H_3O^+(aq) + CH_3CO_2^-(aq)](https://tex.z-dn.net/?f=CH_3CO_2H%28aq%29%20%2B%20H_2O%28l%29%20%5Crightleftharpoons%20H_3O%5E%2B%28aq%29%20%2B%20CH_3CO_2%5E-%28aq%29)
We can write the law of mass action for it:
![Ka=\frac{[H_3O^+][CH_3CO_2^-]}{[CH_3CO_2H]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BCH_3CO_2%5E-%5D%7D%7B%5BCH_3CO_2H%5D%7D)
Of course, excluding the water as heterogeneous substances are not included. Then, in terms of the change
due to the dissociation extent, we are able to rewrite it as shown below:
![1.8x10^{-5}=\frac{x*x}{0.100-x}](https://tex.z-dn.net/?f=1.8x10%5E%7B-5%7D%3D%5Cfrac%7Bx%2Ax%7D%7B0.100-x%7D)
Thus, via the quadratic equation or solve, we obtain the following solutions:
![x_1=-0.00135M\\x_2=0.00133M](https://tex.z-dn.net/?f=x_1%3D-0.00135M%5C%5Cx_2%3D0.00133M)
Obviously, the solution is 0.00133M which match with the hydronium concentration, thus, answer is: 1.3×10⁻³ M in scientific notation.
Regards.
Answer:
Name the element: Beryllium
Number of shells: 4
Valence electrons: 2
Explanation:
Explanation:
3CaBr2 + 2K3N → 6KBr + Ca3N2