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Nezavi [6.7K]
3 years ago
11

For each of these equations, determine the change in the number of moles of gas, δngas.?

Chemistry
1 answer:
LuckyWell [14K]3 years ago
8 0
A.) reactants - 0 moles of gas, products - 4 moles of gas, Δn = 4 moles
B.) reactants - 2 moles of gas, products - 2 moles of gas, Δn = 0 moles
C.) reactants - 3 moles of gas, products - 0 moles of gas, Δn = -3 moles
D.) reactants - 1 mole of gas, products - 0 moles of gas, Δn = -1 moles
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3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!!!!!
dangina [55]

Answer:

I think the answer is c!

Explanation:

Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. A chemical substance is composed of one type of atom or molecule. hope this helps you!

8 0
3 years ago
choose any bases that will selectively deprotonate the above acid, that is, any bases that will favor the formation of products.
Zanzabum

In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.

Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.

For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.

To learn more visit:

brainly.com/question/5613072?referrer=searchResults

8 0
2 years ago
The periodic table below shows which elements are metals, nonmetals, and metalloids. the element with the chemical symbol ______
aleksandr82 [10.1K]
H.
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8 0
3 years ago
What volume in L of a 0.724 M Nal solution contains 0.405 mol of Nal?
Setler [38]

Answer:

0.559 L

Explanation:

Step 1: Given data

  • Moles of sodium iodide (n): 0.405 mol
  • Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

V = n/M

V = 0.405 mol/(0.724 mol/L) = 0.559 L

4 0
2 years ago
Read 2 more answers
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