Answer:
The heat absorbed is hence 10.751.21 J
Explanation:
The heat absorbed when 88g of water is heated from 5.8°C to 35 °C is;
Heat = m c ΔT
m = 88.0 g
c = specific heat of water = 4.184 J/g°C
ΔT = ( change in temperature) = ( 35 - 5.8)°C = 29.2°C
Equating these values into the formula, we obtain;
Heat = 88* 4.184 * 29.2
Heat = 10 751.2064 J
Heat = 10 751.21 J (2 d.p)
The heat absorbed is hence 10.751.21 J
The mass of nitric acid required to make the given solution is 0.0627 g.
The given parameters:
- <em>Volume of the acid, V = 250 mL</em>
- <em>pH of the acid, = 2.4</em>
The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

The molarity of the nitric acid is calculated as follows;

The number of moles of the nitric acid is calculated as follows;

The molar mass of nitric acid is calculated as;

The mass of the nitric acid contained in the calculated number of moles is calculated as;

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.
Learn more about molarity of acids here: brainly.com/question/13864682
Answer:
The answer is "
"
Explanation:
We arrange oxoacids to decrease the intensity of acids in this question. Or we may conclude all this from strongest to weakest acids they order oxoacids, that's why above given order is correct.
Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
Solution : Given,
Volume of solution = 500 ml
Molarity of KOH solution = 0.189 M
Molar mass of KOH = 56 g/mole
Formula used :

Now put all the given values in this formula, we get the mass of solute KOH.


Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams