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Vsevolod [243]
3 years ago
10

A car is traveling down a straight road. Which of Newton's laws must be put into effect to cause the car to follow a curve in th

e road?
Chemistry
1 answer:
finlep [7]3 years ago
6 0

Answer:The second law

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Calculate the pH during the titration of 20.00 mL of 0.1000 M dimethylamine, (CH3)2NH(aq), with 0.1000 M HCl(aq) after 21.23 mL
Evgesh-ka [11]

The pH value of the solution is mathematically given as

pH=2.35

<h3>What pH value of the solution?</h3>

Question Parameters:

pH during the titration of 20.00 mL of 0.1000 M dimethylamine,

with 0.1000 M HCl(aq) after 21.23 mL of the acid

Generally, the equation for the  Chemical Reaction  is mathematically given as

(CH3)2NH(aq), +Hcl   ---> <---- (CH3)2NH2Cl(aq)

Therefore

HCl=\frac{0.186mol}{41.86}

HCL=0.00444M

WHere

HClaq--->H+(aq)+Cl-(aq)

Hence

H+=0.00444M

pH= -log{H+}

pH=log(0.00444)

pH=2.35

For more information on Chemical Reaction

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2 years ago
Formula for Sodium Hydrogen Carbonate NaHCO3? or Na2HCO3?
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NaHCO3 is the right answer

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Answer:

Eventually, these individual laws were combined into a single equation—the ideal gas ... We find that temperature and pressure are linearly related, and if the ... then P and T are directly proportional (again, when volume and moles of gas are ... of the variables, and they are more difficult to use in fitting theoretical equations ...

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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Natasha2012 [34]

When carbon reacts with oxygen it forms CO2. This can depicted by the below equation.

C + O2→ CO2

It has been mentioned that when 14.4 g of C reacts with 53.9 g of O2, then 15.5 g of O2 remains unreacted. <u>This indicates that Carbon is the limiting reagent and hence the amount of CO2 produced is based on the amount of Carbon burnt.</u>

C + O2→ CO2

In the above equation , 1 mole of carbon reacts with 1 mole of O2 to produce 1 mole of CO2.

In this case 14.4 g of Carbon reacts with 53.9 of O2 to produce "x"g of CO2.

<u>No of moles = mass of the substance÷molar mass of the substance</u>

No of moles of carbon = 14.4 /12= 1.2 moles

No of moles of O2 = Mass of reacted O2/Molar mass of O2.

No of moles of O2 = (Total mass of O2 burned - Mass of unreacted O2)/32

No of moles of O2 = (53.9-15.5) ÷ 32 = 1.2 moles.

Hence as already discussed 1 mole of Carbon reacts with 1 mole of O2 to produce 1 mole of CO2. In this case 1.2 moles of carbon reacts with 1.2 moles of O2 to produce 1.2 moles of CO2.

Moles of carbon dioxide = Mass of CO2 produced /Molar mass of CO2

Mass of CO2 produced(x) = Moles of CO2 ×Molar mass of CO2

Mass of CO2 produced(x) = 1.2 x 44 = 52.8 g

<u>Thus 52.8 g of CO2 is produced.</u>

5 0
3 years ago
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