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vampirchik [111]
3 years ago
7

The speed of light in a piece of plastic is 1.87 × 10^8 meters per second. What is the absolute index of refraction of this plas

tic?
options:
1.0
1.6
0.67
1.33
Physics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

n = 1.6

Explanation:

The formula for the calculation of the absolute index of refraction is given as follows:

n = \frac{c}{v}

where,

n = index of refraction

c = speed of light in vacuum = 3 x 10⁸ m/s

v = speed of light in the piece of plastic = 1.87 x 10⁸ m/s

Therefore,

n = \frac{3\ x\ 10^8\ m/s}{1.87\ x\ 10^8\ m/s}

<u>n = 1.6</u>

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Explain why gases are more compressible than solid
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3 years ago
If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 50.5 m/s in the opposite directi
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Answer:

The magnitude of change in momentum of the ball is 97.5 m and impulse is also 97.5 m

Explanation:

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Velocity of a pitched ball v _{i} = 47 \frac{m}{s}

Velocity of ball after impact v_{f}  = -50.5 \frac{m}{s}

From the formula of change in momentum,

  \Delta P = m (v_{f} -v_{i}  )

Here mass is not given in question,

Mass of ball is m

Change in momentum is given by,

\Delta P = m (-50.5 -47)

\Delta P = -97.5 m

Magnitude of change in momentum is

\Delta P = 97.5 m

And impulse is given by

 J = \Delta P

J = -97.5 m

So impulse and

Therefore, the magnitude of change in momentum of the ball is 97.5 m and impulse is also -97.5 m

6 0
3 years ago
a runner moves 2.88 m/s north. she accelerates at 0.350 m/s2 at -52.0 angle. at the point where she is running directly east, wh
Naily [24]

Answer:

11.7 m

Explanation:

I assume north is the y direction and x is the east direction, so Δx refers to the displacement in the east direction.

First, find the time it takes for the velocity to change from directly north to directly east.

Given (in the y direction):

v₀ = 2.88 m/s

v = 0 m/s

a = 0.350 m/s² sin(-52.0°) = -0.276 m/s²

Find: t

v = at + v₀

(0 m/s) = (-0.276 m/s²) t + (2.88 m/s)

t = 10.4 s

Given (in the x direction):

v₀ = 0 m/s

a = 0.350 m/s² cos(-52.0°) = 0.215 m/s²

t = 10.4 s

Find: Δx

Δx = v₀ t + ½ at²

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Δx = 11.7 m

7 0
3 years ago
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