Question

How many grams of ammonia are present in 5.0 L of a 0.050 M solution

Answer 1

Answer:

4.25g

Explanation:

Molar concentration or molarity can be calculated thus;

Molarity (M) = number of moles (n) ÷ volume (V)

According to the provided information in this question, Volume = 5.0L, M = 0.050 M

number of moles = molarity × volume

n = 0.050 × 5

n = 0.25moles

Number of moles in a substance = mass (M) ÷ molar mass (MM)

Molar mass of ammonia (NH3) = 14 + 1(3)

= 17g/mol

Mass = moles × molar mass

Mass (g) = 0.25 × 17

Mass = 4.25g