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shtirl [24]
3 years ago
6

Classify each of these reactions. A single reaction may fit more than one classification. Ba ( ClO 3 ) 2 ⟶ BaCl 2 + 3 O 2 Ba(ClO

3)2⟶BaCl2+3O2 double‑displacement (a.k.a. exchange or metathesis) combination (synthesis) displacement decomposition redox NaNO 2 + HCl ⟶ NaCl + HNO 2 NaNO2+HCl⟶NaCl+HNO2 decomposition displacement combination (synthesis) redox double‑displacement (a.k.a. exchange or metathesis) CaO + CO 2 ⟶ CaCO 3 CaO+CO2⟶CaCO3 double‑displacement (a.k.a. exchange or metathesis) displacement decomposition redox combination (synthesis) ZnSO 4 + Mg ⟶ Zn + MgSO 4 ZnSO4+Mg⟶Zn+MgSO4 double‑displacement (a.k.a. exchange or metathesis) displacement decomposition combination (synthesis) redox
Chemistry
1 answer:
Lena [83]3 years ago
4 0

Answer: a) Ba(ClO_3)_2\rightarrow BaCl_2+3O_2:  Decomposition

b) NaNO_2+HCl\rightarrow NaCl+HNO_2: double displacement

c) CaO+CO_2\rightarrow CaCO_3: Synthesis (Combination)

d) ZnSO_4+Mg\rightarrow MgSO_4+Zn: redox

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

Ba(ClO_3)_2\rightarrow BaCl_2+3O_2

A double displacement reaction is one in which exchange of ions take place.

NaNO_2+HCl\rightarrow NaCl+HNO_2

Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

CaO+CO_2\rightarrow CaCO_3

Redox reaction is a type of chemical reaction in which oxidation and reduction takes place in one single reaction. The oxidation number of one element increases and the oxidation number of other element decreases.

ZnSO_4+Mg\rightarrow MgSO_4+Zn

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Answer:

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What is the number of electrons shared in the multiple carbon-carbon bond in one molecule of 1-pentyne?
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Explain why photosynthesis and cellular respiration are the “real circle of life”
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4 0
3 years ago
Suppose that coal of density 1.5 g/cm^3 is pure carbon. (It is, in fact, much more complicated, but this is a reasonable first a
NISA [10]

Answer:

q = -6464.9 kJ

Explanation:

We are given that the heat of combustion is  ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.

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7 0
3 years ago
The mass percentage of hydrochloric acid within a solution is 28.00%28.00% . Given that the density of this solution is 1.1411.1
sashaice [31]

Answer:

8.76M

Explanation:

Given that

Mass from the density = 1141g

According to the given situation the computation of molarity of the solution is shown below:-

we will took HCL solution which is 1000mL

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So,

Mass of HCl in 1-litre solution is

= \frac{28}{100} \times 1141

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Now,

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= \frac{319.48}{36.45}

Which gives results of molarity is

= 8.76M

8 0
3 years ago
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