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3 years ago

How many moles are contained in the stp 22.4l of n2?

Chemistry

1 answer:

statuscvo [17]3 years ago

8 0

One mole of any gas under STP has volume 22.4 L,
so 22.4 L N2 under STP contains 1 mole of molecules N2.

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What is a characteristic that can be observed or measured without changing the chemical makeup of a substance? *

olga55 [171]

The correct answer is B

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2 years ago

Meteorologists use weather balloons to carry weather instruments high into the atmosphere. When it is first released at Earth’s

ahrayia [7]

The balloons volume as it rises increases because at higher altitude external pressure is lower, so the air molecules inside the balloons tends to expand more to attain mechanical equilibrium, where the external pressure and internal pressure are equal. Unlike when the balloon is on the ground, external pressure is great so the gas molecule cannot push the walls of the balloon so it is like underinflated.

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3 years ago

Read 2 more answers

Complete the following reaction : HC≡CH + HBr→?

Morgarella [4.7K]

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2 years ago

How many grams of NaCL are required to prepare 50ml of a 2.0 molar solution

Ksivusya [100]

Answer:

5.85 gm.

Explanation:

We know that,

Normality = Molarity × Molecular weight

Equivalent weight

Since molecular weight of NaCl= equivalent weight = 23+35.5 =58.5

Normality of NaCl= molarity=2

Now,

Normality= weight in gram ×1000

Volume ×equivalent weight

Weight in gram is given by,

=Normality × Volume × equivalent weight

1000

= 2× 50 × 58.5

1000

=5.85 gm.

4 0

3 years ago

Prob.: Consider the combustion of butane (C4H10):

never [62]

Answer: The moles of carbon dioxide formed in the reaction is 20 moles.

Explanation:

We are given:

Number of moles of butane = 5.0 moles

The chemical reaction for the combustion of butane follows the equation:

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(l)$

As, oxygen is present in excess. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of products.

By stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide.

So, 5 moles of butane will produce = $\frac{8}{2}\times 5=20mol$ of carbon dioxide.

Hence, the moles of carbon dioxide formed in the reaction is 20 moles.

7 0

3 years ago