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Nonamiya [84]
3 years ago
15

Burning is a reaction in which oxides are formed by combining ______ and _________.

Chemistry
2 answers:
Romashka [77]3 years ago
4 0
Carbon with monoxide
Alchen [17]3 years ago
4 0

Answer:

Burning is a reaction in which oxides are formed by combining fuel(reductant) and oxidant.

Explanation: Ex charcoal and lighter fluid

Hope this helps

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Consider the reaction: 2HI(g) ⇄ H2(g) + I2(g). It is found that, when equilibrium is reached at a certain temperature, HI is 35.
Sliva [168]

Answer:

Kc = 0.075

Explanation:

The dissociation (α) is the initial quantity that ionized divided by the total dissolved. So, let's calling x the ionized quantity, and M the initial one:

α = x/M

x = M*α

x = 0.354M

For the stoichiometry of the reaction (2:1:1), the concentration of H₂ and I₂ must be half of the acid. So the equilibrium table must be:

2HI(g) ⇄   H₂(g) +    I₂(g)

M               0             0               <em> Initial</em>

-0.354M  +0.177M  +0.177M       <em>Reacts</em>

0.646M     0.177M   0.177M        <em>Equilibrium</em>

The equilibrium constant Kc is the multiplication of the products' concentrations (elevated by their coefficients) divided by the multiplication of the reactants' concentrations (elevated by their coefficients):

Kc = \frac{[H2]*[I2]}{[HI]^2}

Kc = \frac{0.177M*0.177M}{(0.646M)^2}

Kc = \frac{0.03133M^2}{0.41732M^2}

Kc = 0.075

5 0
3 years ago
What Is the answers?
Yuki888 [10]

Answer:

oxygen is responsible for rusting

5 0
2 years ago
Read 2 more answers
I have no idea how to do this and need help
den301095 [7]

Answer:

60.55%

Explanation:

nO3=155/48

nO2 used: 3/2nO3=4.84375

percent yield: 4.84375/8=60.55%

5 0
3 years ago
While 1 gram of fat provides 9 calories, 1 gram of glucose provides 4 calories. Why is that?
seropon [69]

Answer:

fat always has more calories than glucose does

Explanation:

hope hope this helps!

6 0
3 years ago
2Al + 3Br2 --&gt; 2AlBr3
vlada-n [284]
A) The limiting reactant is Al
b) Br2 is the excess reactant
c) The amount moles of AlBr3 that get produced will be equal to the number of moles of Al to begin with.
d) 0
4 0
3 years ago
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