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4 years ago

What 3 pieces of information do you need when describing an object's motion?

1 answer:

7 0

Answer: To describe an object’s motion, you must have a distance, km, mm, m, a speed, and time to show how long, seconds, minuets, hours, days.

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the mass of a 125 cm3 piece of material is 82.75 g. determine the density of this material . please explain

andre [41]

You would do 82.75 divided by 125 cm3 and get 0.6620 g/cm3 because to find density you mist divide mass and volume and grams is always mass and cm3 or mL is always volume. hope i helped!

6 0

4 years ago

Place each statement in the column of the particle that it best describes.<br> Refer To Photo

MrRa [10]

The options are labelled as:

1 2

3 4

5 6

7 8

Protons: 1, 5, 7

Neutrons: 2, 8

Electron: 3, 4, 6

5 0

3 years ago

Consider the heating curve for water. A graph of the heating curve for water has time in minutes on the horizontal axis and Temp

Zolol [24]

Answer:

0°C.

Explanation:

Hello,

In this case, given the heating curve of water on the attached document, we can notice that at 0 °C the solid starts melting, which means that the melting point is reached. Melting point is known as a physical change whereby a solid changes to liquid by the addition of heat as it allows the molecules to separate to each other.

Best regards.

4 0

3 years ago

Write the balanced chemical equation between H2SO4 and KOH in aqueous solution. This is called a neutralization reaction and wil

emmainna [20.7K]

Answer:

0.166M

Explanation:

In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:

<em>Moles H2SO4:</em>

0.650L * (0.430mol /L) = 0.2795moles H2SO4

<em>Moles KOH:</em>

0.600L * (0.240mol / L) = 0.144 moles KOH

Moles of sulfuric acid that reacts with 0.144 moles of KOH are:

0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.

And remain:

0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.

In 0.650L + 0.600L = 1.25L:

Molar concentration of sulfuric acid:

0.2075 moles of H2SO4 / 1.25L =

7 0

3 years ago

1. How is the law of conservation of mass shown by a balanced chemical equation?

Ilia_Sergeevich [38]

Answer:

Explanation:

hope this helps

3 0

3 years ago