Answer:
1.42 Kg of NaHCO3
Explanation:
From
Co= 10 pd/M
Where;
Co= concentration of the stock solution of acid
p= percentage of raw acid = 36%
d= density of the acid= 1.138g/mL
M= molar mass of the acid= 36.5 g/mol
Co= 10 × 36 × 1.138/36.5
Co= 11.22 M
Number of moles of acid= CV = 11.22 M × 1.508 L= 16.9 moles
The reaction equation is;
NaHCO3(aq)+HCl(aq)→NaCl(aq)+H2O(l)+CO2(g)
If 1 mole of NaHCO3 reacts with 1 mole of HCl
Then 16.9 moles of HCl reacts with 16.9 moles of NaHCO3
Hence 16.9 moles of NaHCO3 is required to neutralize the HCl.
From
n= m/ M
Where;
n= number of moles = 16.9
m= mass of NaHCO3= ??
M= molar mass of NaHCO3= 84.007 g/mol
m= n× M/1000
m= 16.9 × 84.007 /1000
m= 1.42 Kg
Explanation:
We assume that is represented by A and is represented by B respectively.
According to Wilke Chang equation as follows.
where, T = absolute temperature = (273 + 37)K = 310 K
= an association parameter for solvent water = 2.26
= Molecular weight of water = 18 g/mol
= viscosity of water (in centipoise) = 0.62 centipoise
= the molar volume of oxygen = 25.6
Hence, putting the given values into the above formula as follows.
=
=
Thus, we can conclude that the diffusion of in water by the Wilke-Chang correlation at .
Mike would be right, since there are only 3 electrons in the shell, if shows that there are 3 protons. Lithium is the only element with 3 protons
Answer:
0.1 is the mole fraction of glucose.
Explanation:
Mas of glucose = 180 g
Moles of glucose =
Mass of water = 162 g
Moles of water =
Mole fraction of glucose =
0.1 is the mole fraction of glucose.