Question

3. ml of 1.00 M LiOH to 500.00 ml of 0.075 M of LiOH (Dilution Problem)​

Answer 1

The volume (in mL) of the 1.00 M LiOH needed to prepare 500.00 mL of 0.075 M of LiOH is 37.5 mL

How do I determine the volume (in mL) of LiOH needed?

Dilution formula is given as follow:

M₁V₁ = M₂V₂

Where

• M₁ is the molarity of stock solution
• V₁ is the volume of stock solution
• M₂ is the molarity of diluted solution
• V₂ is the volume of diluted solution

Applying the above formula, we obtain the volume (in mL) of LiOH needed to prepare 500.00 mL of 0.075 M of LiOH. This is illustrated below:

• Molarity of stock solution of LiOH (M₁) = 1.00 M
• Volume of diluted solution of LiOH (V₂) = 500.00 mL
• Molarity of diluted solution of LiOH (M₂) = 0.075 M
• Volume of stock solution of LiOH needed (V₁) =?

M₁V₁ = M₂V₂

1 × V₁ = 0.075 × 500

V₁ = 37.5 mL

Thus, the volume (in mL) of LiOH needed is 37.5 mL

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