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Harrizon [31]
1 year ago
9

3. ml of 1.00 M LiOH to 500.00 ml of 0.075 M of LiOH (Dilution Problem)​

Chemistry
1 answer:
castortr0y [4]1 year ago
6 0

The volume (in mL) of the 1.00 M LiOH needed to prepare 500.00 mL of 0.075 M of LiOH is 37.5 mL

<h3>How do I determine the volume (in mL) of LiOH needed?</h3>

Dilution formula is given as follow:

M₁V₁ = M₂V₂

Where

  • M₁ is the molarity of stock solution
  • V₁ is the volume of stock solution
  • M₂ is the molarity of diluted solution
  • V₂ is the volume of diluted solution

Applying the above formula, we obtain the volume (in mL) of LiOH needed to prepare 500.00 mL of 0.075 M of LiOH. This is illustrated below:

  • Molarity of stock solution of LiOH (M₁) = 1.00 M
  • Volume of diluted solution of LiOH (V₂) = 500.00 mL
  • Molarity of diluted solution of LiOH (M₂) = 0.075 M
  • Volume of stock solution of LiOH needed (V₁) =?

M₁V₁ = M₂V₂

1 × V₁ = 0.075 × 500

V₁ = 37.5 mL

Thus, the volume (in mL) of LiOH needed is 37.5 mL

Learn more about volume:

brainly.com/question/24159217

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Which of these solutions are basic at 25 °C? Solution A: [OH−]=3.13×10−7 M Solution C: [H3O+]=0.000747 M Solution B: [H3O+
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Answer:

Are basic:

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Explanation:

A solution is basic when pH = - log [H₃O⁺] is higher than 7.

It is possible to convert [OH⁻] to [H₃O⁺] using:

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