Answer:
0.897 J/g.⁰C
Explanation:
Given the following data:
m = 170 g (mass)
ΔT = 20.0⁰C (change in temperature)
q = 3050 J (amount of heat)
The amount of heat (q) is calculated as follows:
q = m x Cp x ΔT
Thus, we introduce the data in the mathematical expression to calculate the specific heat (Cp):
Cp = q/(m x ΔT) = 3050 J/(170 g x 20.0⁰C) = 0.897 J/g.⁰C
The atom that is oxidized : Cr
The oxidizing agent : H₃PO₄
<h3>Further explanation</h3>
Reaction
2 H₃PO₄ (aq) + 2Cr(s) → 2 CrPO₄ (aq) + 3H₂(g)
Atoms undergoing a reduction reaction (decrease in oxidation number) and an oxidation reaction (increase in oxidation number)
H⁺(in H₃PO₄) =+1
H₂=0
Cr = 0
Cr³⁺(in CrPO₄ )
the oxidizing agent.⇒which undergoes a reduction reaction and oxidizes another compound/element : H₃PO₄
Answer:
1. magnesium chloride
2. lithium chloride
3. 2
Explanation:
Know how to figure names (their are rules, be familiar with them)
Count the number
- Hope that helps! Let me know if you need further explanation.
B i think but im not 100 percent sure
Answer:
The type of reaction is a single-replacement reaction.
Explanation:
Mg switches places with H, leaving H by itself.
