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BartSMP [9]
2 years ago
5

6. A student notices that when a weight is hung on a spring, the spring stretches. She decides conduct an experiment to determin

e the relationship between the amount of weight
placed on a spring and the distance the spring stretches. She has five different weights: 25 9,50 9.75 9, 1009, and 125 g. She selects a weight, hangs it on the spring, and
measures how far the spring stretches
What is the dependent variable in this experiment?
O weight hung from the spring
O temperature of the spring
length of unstretched spring
distance the spring stretches
Physics
1 answer:
natima [27]2 years ago
4 0

Answer:

D

Explanation:

She says that the object of the experiment is to see how far the string stretches given a mass attached to the string.

The only thing that is at issue is either the mass or the amount the string stretches.

Nothing else matters.

The dependent variable therefore is the amount the string stretches. So the last choice is the answer.

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A 975-kg sports car (including driver) crosses the rounded top of a hill at determine (a) the normal force exerted by the road o
iVinArrow [24]
There are missing data in the text of the problem (found them on internet):
- speed of the car at the top of the hill: v=15 m/s
- radius of the hill: r=100 m

Solution:

(a) The car is moving by circular motion. There are two forces acting on the car: the weight of the car W=mg (downwards) and the normal force N exerted by the road (upwards). The resultant of these two forces is equal to the centripetal force, m \frac{v^2}{r}, so we can write:
mg-N=m \frac{v^2}{r} (1)
By rearranging the equation and substituting the numbers, we find N:
N=mg-m \frac{v^2}{r}=(975 kg)(9.81 m/s^2)-(975 kg) \frac{(15 m/s)^2}{100 m}=7371 N

(b) The problem is exactly identical to step (a), but this time we have to use the mass of the driver instead of the mass of the car. Therefore, we find:
N=mg-m \frac{v^2}{r}=(62 kg)(9.81 m/s^2)-(62 kg) \frac{(15 m/s)^2}{100 m}=469 N

(c) To find the car speed at which the normal force is zero, we can just require N=0 in eq.(1). and the equation becomes:
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