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olga nikolaevna [1]
4 years ago
15

Consider the hypothesis below and answer the question that follows. Adding salt to water increases the water’s boiling point. If

you performed an experiment to test this hypothesis, which action would introduce confounding variables into your experiment?
You use distilled water sourced from the same place.
You add black salt to some specimens and pink salt to others.
You add equal quantities of salt in all the water specimens.
You use earthen clay pots to store and boil all the water specimens.
Physics
2 answers:
irakobra [83]4 years ago
8 0
The hypothesis because its very hard to make and it confounds me
Tju [1.3M]4 years ago
7 0

Answer C. You add equal quantities of salt in all the water specimens.

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Only living things have energy T or F?
Angelina_Jolie [31]

Answer:

. living things only have energy : true.

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3 years ago
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50g of ice at 0°C is mixed with 50g of water at 80°C, what will be the final temperature of a mixture in
xxTIMURxx [149]

Answer:

0° C

Explanation:

Given that

Mass of ice, m = 50g

Mass of water, m(w) = 50g

Temperature of ice, T(i) = 0° C

Temperature of water, T(w) = 80° C

Also, it is known that

Specific heat of water, c = 1 cal/g/°C

Latent heat of ice, L(w) = 89 cal/g

Let us assume T to be the final temperature of mixture.

This makes the energy balance equation:

Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C

m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have

50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)

4000 + 50T = 4000 - 50T

0 = 100 T

T = 0° C

Thus, the final temperature is 0° C

3 0
3 years ago
What are the sign and magnitude of a point charge that produces an electric potential of −2.36 V at a distance of 2.93 mm?
Blababa [14]

Answer:

q = -7.691 × 10^{-13} C

so magnitude of charge is 7.691 × 10^{-13} C

and negative sign mean charge is negative potential

Explanation:

given data

electric potential = −2.36 V

distance = 2.93 mm = 2.93 × 10^{-3} m

to find out

What are the sign and magnitude of a point charge

solution

we know here that electric potential due to charge is

V = k\frac{q}{r}       ..............................1

here k is coulomb force that is 8.99 ×10^{9} Nm²/C² and r is distance and q is charge  and V is electric potential

put here all value we get q  in equation 1

V = k\frac{q}{r}

-2.36 = 8.99*10^{9} \frac{q}{2.93*10^{-3}}

q = -7.691 × 10^{-13} C

so magnitude of charge is 7.691 × 10^{-13} C

and negative sign mean charge is negative potential

6 0
3 years ago
Can someone help me please?
Drupady [299]
D is the right answer
5 0
4 years ago
When nuclear fission occurs _____.
Burka [1]
In case of nuclear fission, the heavier nucleus captures the neutron and splits themselves into daughter nucleus or small fragments. The sum of mass of the fragments is less than the original mass. The missing mass is converted into energy according to Einstein's mass-energy equivalence relation. 
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