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olga nikolaevna [1]
3 years ago
15

Consider the hypothesis below and answer the question that follows. Adding salt to water increases the water’s boiling point. If

you performed an experiment to test this hypothesis, which action would introduce confounding variables into your experiment?
You use distilled water sourced from the same place.
You add black salt to some specimens and pink salt to others.
You add equal quantities of salt in all the water specimens.
You use earthen clay pots to store and boil all the water specimens.
Physics
2 answers:
irakobra [83]3 years ago
8 0
The hypothesis because its very hard to make and it confounds me
Tju [1.3M]3 years ago
7 0

Answer C. You add equal quantities of salt in all the water specimens.

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I need homework help
KIM [24]
1) the weight of an object at Earth's surface is given by F=mg, where m is the mass of the object and g=9.81 m/s^2 is the gravitational acceleration at Earth's surface. The book in this problem has a mass of m=2.2 kg, therefore its weight is 
F=mg=(2.2 kg)(9.81 m/s^2)=21.6 N

2) On Mars, the value of the gravitational acceleration is different:g=3.7 m/s^2. The formula to calculate the weight of the object on Mars is still the same, but we have to use this value of g instead of the one on Earth: F=mg=(2.2 kg)(3.7 m/s^2)=8.1 N

3) The weight of the textbook on Venus is F=19.6 N. We already know its mass (m=2.2 kg), therefore by re-arranging the usual equation F=mg, we can find the value of the gravitational acceleration g on Venus: 
g= \frac{F}{m}= \frac{ 19.6 N}{2.2 kg}=8.9 m/s^2

4) The mass of the pair of running shoes is m=0.5 kg. Their weight is F=11.55 N, therefore we can find the value of the gravitational acceleration g on Jupiter by re-arranging the usual equation F=mg: 
g= \frac{F}{m} = \frac{11.55 N}{0.5 kg} =23.1 m/s^2

5) The weight of the pair of shoes of m=0.5 kg on Pluto is F=0.3 N. As in the previous step, we can calculate the strength of the gravity g on Pluto as 
g= \frac{F}{m} = \frac{0.3 N}{0.5 kg} =0.6 m/s^2

<span>6) On Earth, the gravity acceleration is </span>g=9.81 m/s^2<span>. The mass of the pair of shoes is m=0.5 kg, therefore their weight on Earth is 
</span>F=mg=(0.5 kg)(9.81 m/s^2)=4.9 N<span>
</span>
5 0
3 years ago
When the distance between two objects doubles, what happens to the gravitational attraction between these two objects?
Feliz [49]

Answer:

As indicated by Newton's law of attraction each article or body in the universe draws in every single item towards one another and that power of fascination is straightforwardly relative to the result of their masses and contrarily corresponding to the square of the distance between them.  

The power of gravity between two articles will diminish as the distance between them increments. The two most significant elements influencing the gravitational power between two items are their mass and the distance between their focuses. As mass increments, so does the power of gravity, however an increment in distance mirrors a reverse proportionality, which makes that power decline dramatically.  

At that point by Newton's All inclusive Law of Attractive energy;  

F=GMm/R^2  

Mm= result of the majority  

R=Distance Between the two masses by focus.  

On the off chance that R is multiplied, new force=GMm/(2R)^2  

=GMm/4R^2  

Unique Power/New Force=4/1  

F/4=New Power

8 0
3 years ago
Calculate the electrical energy use of the microwave in 120 V circuit has 7.5 A current flow, if it used for 0.05 hours
Elden [556K]

Answer:

162 KJ

Explanation:

The electrical energy can be calculated using the formula

E = V×I×t

Where, V= voltage = 120 V

I is current in ampere = 7.5 A and t is time in seconds

1 hour = 3600 sec

Therefore, 0.05 hour = 3600×0.05 = 180 sec

Substitute the values in above equation find electrical power

E = 120×7.5×180

= 162000 J

= 162 KJ

Therefore, the electrical energy use of the microwave = 162 KJ

3 0
3 years ago
Can someone please tell me the answer
Anna35 [415]
So here the red ball is initially stationary so V2=0m/s. Plus for the sake of rules the mass must be converted into kg. Initial momentum would equal the final momentum. Make an equation out of it and get the answer.

8 0
3 years ago
There is a bell at the top of a tower that is 95 m high. The mass of the bell is 21 kg. What is the potential energy of the bell
melomori [17]

Answer:

19,551 J!

Explanation:

The formula is PE = ham (h=height, a= acceleration or 9.8, m= mass)

PE = (95)(9.8)(21)

PE = 19,551 Joules

5 0
3 years ago
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