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vladimir2022 [97]
2 years ago
9

The Brahman cattle have good resistance to high temperature, but its meat is poor and tough to eat. The English shorthorn cattle

, on the other hand, have good meat, but poor resistance to high temperatures. Farmers formed the Santa Gertrudis cattle by breeding Brahmans with English shorthorns. This new type of cattle has good meat and resistance to high temperatures. Which of the following best describes the process used to produce the Santa Gertrudis cattle?
A.
genetic engineering

B.
inbreeding

C.
natural selection

D.
selective breeding
Chemistry
2 answers:
Scorpion4ik [409]2 years ago
7 0
D because Selective breeding is the process by which humans use animal breeding to selectively develop particular phenotypic traits by choosing which typically animal males and females will sexually reproduce and have offspring together. Which is what the farmer should do to make his cattle much more better
N76 [4]2 years ago
4 0

Answer:

d

Explanation:

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frez [133]
If you could explain what “merkels” are, the question would be more clear.
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If the E°cell value = +0.46V and E°(Ag+/Ag) = +0.80V
fenix001 [56]

Answer:

0.34

Explanation:

Cu>>>Cu2+(oxidation number increases)[Oxidation occurs]

Ag+>>>Ag(Oxidation number decreases) [Reduction occurs]

E°=0.80-0.46

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8 0
1 year ago
Read 2 more answers
The answer to question 2
Bad White [126]

Answer:


12


Explanation:


You will need a chemical equation with masses and molar masses, so let’s gather all the information in one place.


M_{r}:                           258.21       18.02


                 KAl(SO₄)₂·xH₂O ⟶ KAl(SO₄)₂ + xH₂O


Mass/g:             4.74                                       2.16


Step 1. Calculate the mass of the KAl(SO₄)₂.


Mass = 4.74 g – 2.16 g = 2.58 g.


Step 2. Calculate the moles of each product.


\text{Moles of KAl(SO}_{4})_{2} = \text{2.58 g} \times \frac{\text{1 mol} }{\text{258.21 g}} = 9.992 \times 10^{-3} \text{ mol}

\text{Moles of H}_{2}\text{O} = \text{2.16 g} \times \frac{\text{1 mol} }{\text{18.02 g}} = \text{ 0.1200 mol}

Step 3. Calculate the molar ratio of the two products.


\frac{\text{Moles of KAl(SO}_{4})_{2}}{\text{Moles of H}_{2}\text{O}} = \frac{ 9.992 \times 10^{-3} \text{ mol}}{\text{ 0.1200 mol} } = \frac{1 }{12.01} \approx \frac{ 1}{ 12}

1 mol of KAl(SO₄)₂ combines with 12 mol H₂O, so x = 12.



3 0
3 years ago
The overall reaction of ozone reacting to form oxygen has been proposed to occur in a reaction mechanism of: What is the role of
LekaFEV [45]

Answer:

3) O(g) is an intermediate; 2O3(g)→3O2(g)

Explanation:

The decomposition of ozone to yield oxygen occurs in a sequence of steps. The various non-elementary reactions involved constitute the reaction mechanism. In the sequence of reaction steps O(g) serves as an intermediate.

The overall reaction involves the conversion of two moles of ozone to three moles of oxygen as shown in the answer. Thus the O(g) is merely a reaction intermediate.

8 0
2 years ago
What is the normal ph of rain?
Nuetrik [128]
Since rain is water getting evaporated and condensed, it's equivalent to being distilled. Distilled water is pure water, so I'd guess the normal pH of rain is 7 - which is neutral (neither acidic nor alkaline)

However, when Sulfur Oxides and Nitrogen Oxides mix into the clouds, acid rain could be produced. This isn't "normal rain", though
5 0
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