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antiseptic1488 [7]
3 years ago
8

Why the bond in water molecule os polar covalent bond, while than in chlorine molecule is pure covalent bond? Give reason? ​

Chemistry
1 answer:
erastovalidia [21]3 years ago
8 0

Explanation:

The unequal sharing of electrons between the atoms and the unsymmetrical shape of the molecule means that a water molecule has two poles - a positive charge on the hydrogen pole (side) and a negative charge on the oxygen pole (side). We say that the water molecule is electrically polar.

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How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif
Katena32 [7]

<u>Answer:</u> The number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

<u>Explanation:</u>

Formula units are defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is 6.022\times 10^{23}

We are given:

Number of formula units of Sr(HCO_3)_2=4.55\times 10^{15}

As, 6.022\times 10^{23}  number of formula units are contained in 1 mole of a substance.

So, 4.55\times 10^{15} number of formula units will be contained in = \frac{1}{6.022\times 10^{23}}\times 4.55\times 10^{15}=7.5\times 10^{-9}mol of strontium bicarbonate.

Hence, the number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

5 0
3 years ago
A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe
Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: V_{1} = 571 mL,       T_{1} = 26^{o}C

(a) T_{2} = 5^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL

(b) T_{2} = 95^{o}F

Convert degree Fahrenheit into degree Cesius as follows.

(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL

(c) T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL

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2 years ago
All of the following will be damaging to the environment except
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