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kow [346]
3 years ago
6

Why is is not letting me see answers =(

Physics
1 answer:
Llana [10]3 years ago
3 0
You might have to refresh or turn off and on the electronic
You might be interested in
Since sound is a mechanical wave it needs a ...... to travel through
Leni [432]

Answer:

medium

Examples:

A medium is a thing that the sound wave would travel through, like sound waves traveling through air. A mechanical wave cannot travel without a medium, like if the wave were trying to travel through a vacuum.

6 0
3 years ago
A) Using Excel, or some other graphing software, plot the values of y as a function of x. (You will not submit this spreadsheet.
tiny-mole [99]

Answer:

   y = 1.06 x + 0.14

            r² = 0.95

Explanation:

a) To make this graph, a spreadsheet-type calculation program is used, see attached.

On the y axis are the measured values

On the x-axis, the values ​​checked in the experiment are placed.

From the graph we see that a linear graph and that one of the values ​​has a strong deviation with respect to the others

b) The red line is the best straight line that can be drawn,

    for this the quality ajust is r²  

the closer to 1 the better the fit

           

the equation of the line is

            y = 1.06 x + 0.14

            r² = 0.95

3 0
3 years ago
A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o
Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m

The fundamental frequency of the wire is given by

f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N

The tension in the wire is 67.9064 N

7 0
3 years ago
Which statement describes the use of control rods?
Anit [1.1K]
Control rods<span> are </span>rods<span>, plates, or tubes containing a neutron absorbing material (material with high absorbtion cross-section for thermal neutron) such as boron, hafnium, cadmium, etc., used to </span>control<span> the power of a nuclear reactor.
so the statement that describe a control rod is:
</span><span>Control rods are lowered into the reactor to slow down the reaction by absorbing neutrons.</span>
6 0
4 years ago
Read 2 more answers
What is the requirement for a core to be used in an electromagnet?
mr_godi [17]
<span> The wire turns are often wound around a magnetic core made from a ferromagnetic or ferrimagnetic material such as iron; the magnetic core concentrates the magnetic flux and makes a more powerful magnet.</span>
5 0
3 years ago
Read 2 more answers
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