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nadya68 [22]
3 years ago
13

Which term refers to the structure that forms the surface of a cell separating its contents from outside world

Physics
2 answers:
Elodia [21]3 years ago
6 0
I think it is the plasma membrane

PolarNik [594]3 years ago
4 0

Same thing that Boyer23 said, Plasma Membrane, but plasma membrane means the same thing as Cell Membrane! I hope this helps! :)

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What is arcsecond definition
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Answer:

An arcsecond, also called a second of an arc, is a unit of measurement that amounts to one sixtieth of an arcminute. Simply put, it is equal to 1/3600 degrees of an arc. The symbol used to mark an arcsecond is the double quote.

Explanation:

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In what way do sound waves differ from radio waves?.
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Radio waves are a type of electromagnetic wave that can travel when there is no medium, whereas sound waves are a type of mechanical wave that cannot travel if there is no medium
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2 years ago
A force acting on a moving ball causes its motion to change. This force stays constant.
sashaice [31]

Answer:

you stop the ball or bring it to a different direction

Explanation:

i don't know if this helps. i didn't take physics yet. but i hope this helps.

8 0
3 years ago
What is the mass of a substance that has a density of 5g/ml and the volume of 3ml
Lina20 [59]

Answer:

m= 15g/0.015 kg

Explanation:

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3 0
3 years ago
The water is flowing through the horizontal constricted pipe. The pressure at one end is 4500Pa, speed is 3m/s and area of cross
Oksana_A [137]

The speed and pressure at another end will be 9 m/sec and -31500 pascals.

<h3>What is gauge pressure?</h3>

The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.

Given data in problem is;

For horizontal pipe, Z₁=Z₂

Pressure at end 1, P₁ = 4500Pa

Speed at end 1, V₁ = 3 m/sec

Speed at end 2, V₂ = ? m/sec

Area of cross-section at end 1,A₁ =A

Area of cross-section at end 1,A₂ = A/3

From the continuity equation;

A₁V₁=A₂V₂

A× 3  = (A/3)×V₂

V₂ = 9 m/sec

From Bernoulli's equation;

\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2  \\\\ \frac{P_1-P_2}{\rho g } = \frac{v_2^2-v_1^2}{2g} \\\\ \frac{P_1-P_2}{\rho} =  \frac{v_2^2-v_1^2}{2} \\\\ \frac{4500-P_2}{1000} =  \frac{9^2-3^2}{2} \\\\ 4500 -P_2 = 36000 \\\\ P_2 =  - \ 31,500 \ pa

Hence the speed and pressure at another end will be 9 m/sec and -31500 pascals.

To learn more about the gauge pressure, refer to the link;

brainly.com/question/14012416

#SPJ1

7 0
2 years ago
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