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ioda
3 years ago
14

How will the solubility of a gas solute change if the pressure above the solution is reduced?

Physics
2 answers:
Hoochie [10]3 years ago
6 0
If the pressure above a solution containing a gas solute is reduced, the limit of the gas's solubility will decrease.
labwork [276]3 years ago
6 0

Answer:

The limit of the gas's solubility will decrease.

Explanation:

The solubility of a gas in a liquid is explained by Henry's law.

S = k . P

where,

S is the solubility of the gas

k is the Henry's constant (depends on each gas)

P is the partial pressure of the gas (at equilibrium with the pressure above the solution)

We can see that the solubility is directly proportional to the pressure. If the pressure is reduced, the solubility decreases.

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Describe the valence electrons in nitrogen and how it could bond to other atoms?
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Answer:

Each nitrogen molecule consists of two atoms of nitrogen that are bonded by a triple covalent bond. This is because each nitrogen atom has 5 valence electrons. Each atom can complete its octet by sharing three electrons.

I hope this helps!

4 0
3 years ago
Which statement best explains how a planet affects the orbit of a comet as the comet passes by the planet?
mezya [45]
Comets orbit the sun just like planets do. Except a comet usually has a very elongated orbit. Thanks to the laws of gravity comets obey the same laws. A comets orbit takes it very close to the sun and then far away again.
8 0
2 years ago
Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.
Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = \frac{mv}{qB}

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and  charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r =  \frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T} = 0.0328 m, or 3.28  cm.

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3 years ago
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