Explanation:
What is the weight of a 2.00-kilogram object on the surface of Earth?
2.00 N
4.91 N
9.81 N
19.6 N
Given parameters:
Mass of the object = 2kg
Unknown:
Weight of the object = ?
Solution:
The weight of an object is the force of gravity acting on the object;
Weight = mass x acceleration due to gravity
Acceleration due to gravity = 9.8m/s²
Now insert the parameters and solve;
Weight = 2 x 9.8 = 19.6N
A person weighing 785 Newtons on the surface of the Earth would weigh 47 Newtons on the surface of Pluto. What is the magnitude of the gravitational acceleration on the surface of Pluto?
1.7 m/s²
0.59 m/s²
0.29 m/s²
9.8 m/s²
Given parameters:
Weight on Earth = 785N
Weight on Pluto = 47N
Unknown:
Acceleration due to gravity on Pluto = ?
Solution
The mass of the body both on Earth and Pluto is the same.
Weight = mass x acceleration due to gravity
Now find the mass on Earth;
Acceleration due to gravity on Earth = 9.8m/s²
785 = mass x 9.8
mass = 
= 80.1kg
So;
Acceleration due to gravity on Pluto = 
Acceleration due to gravity = 
= 0.59m/s²
The answer to this question is "LIES BELOW THE SURFACE" happens or occurs. When one of the main differences between the two which is the Intaglio and the other one is the relief printing processes is that with the Intaglio the ink LIES BELOW the surface of the printing plate.
Answer:
<h2>
3.94 kg</h2>
Explanation:
Given,
Force ( f ) = 30 N
Acceleration(a) = 7.6 m/s
Now, Let's find the mass of the ball
Using the Newton's second law of motion:
We get:
plug the value
Use the commutative property to reorder the terms
Swap the sides of the equation
Divide both sides of the equation by 7.6
Calculate
Hope this helps..
Best regards!!
Explanation:
You walk 53m to the north, then you turn 60° to your right and walk another 45m. Determine the direction of your displacement vector. Express your answer as an angle relative to east
Answer:
work output is always less than work input - the ratio is less than 1.
Explanation:
This principle comes from the fact that a machine or system cannot produce more work than is supplied to it, because this would violate the energy conservation law (work is a type of mechanical energy).
In theoretical machines called "ideal machines" the input work is the same as the output work, but these machines are only theoretical because in real applications there is always some type of energy loss, either in heat produced by a machine or processes for its operation, for this reason the output work is always less than the input work.
Regarding the ratio work output to work input:
because work input WI is always greater than work output WO.
