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telo118 [61]
4 years ago
7

If 4.50 l of water vapor at 50.2 °c and 0.121 atm reacts with excess iron, how many grams of iron(iii) oxide will be produced?

Chemistry
2 answers:
Flura [38]4 years ago
6 0
When the balanced equation for this reaction is:
2Fe + 3H2O → Fe2O3  +  3H2

and according to the vapour pressure formula:
PV= nRT
when we have P is the vapor pressure of H2O= 0.121 atm
and V is the volume of H2O = 4.5 L
and T in Kelvin = 52.5 +273 = 325.5 K
R= 0.08205 atm-L/g mol-K
So we can get n H2O
So, by substitution:
n H2O = PV/RT
            = (0.121*4.5)/(0.08205 * 325.5) = 0.02038 gmol
n Fe2O3 = 0.02038 * (1Fe2O3/ 3H2O) = 0.00679 gmol
Note: we get (1FeO3/3H2O) ratio from the balanced equation.
we can get the Mass of Fe2O3 from this formula:
Mass = number of moles * molecular weight       
  when we have a molecular weight of Fe2O3 = 159.7
          =  0.00679 * 159.7 = 1.084 g
∴ 1.084 gm of Fe2O3 will produced
Oksanka [162]4 years ago
5 0

When the balanced equation for this reaction is:

2Fe + 3H2O → Fe2O3 + 3H2

and according to the formula for vapor pressure:

PV = nRT

when we have P is the vapor pressure H2O = 0.121 atm

and V is the volume of H2O = 4.5 L

and T in Kelvin = 52.5 +273 = 325.5 K

R = 0.08205 atm-L / g mol-K

So we can get H2O

So, with substitution:

n H2O = PV / RT

= (0.121 * 4.5) / (0.08205 * 325.5) = 0.02038 g/mol

n Fe2O3 = 0.02038 * (1Fe2O3 / 3H2O) = 0.00679 g/mol

Note: we get the ratio (1FeO3 / 3H2O) of the balanced equation.

we can get Fe2O3 Mass from this formula:

Mass = number of moles * molecular weight

we have a molecular weight of Fe2O3 = 159.7

= 0.00679 * 159.7 = 1,084 g

So, 1,084 grams will produce Fe2O3

<h2>Further Explanation </h2>

The chemical reaction in the event of chemical change from substances that react (reactants) into substances that result from reactions (products). In chemical reactions, new substances are always produced with new properties. Chemical reactions are written using the element symbol. Let's look at how to express a reaction using symbols.

Material conservation law states that in ordinary chemical reactions no material is lost even though it might change. The number of atoms in reagents must remain the same as those produced, however, they change to form new molecular patterns. If an equation fulfills the conditions, it can be said that the equation is balanced.

Characteristics of Chemical Reactions

When a chemical reaction occurs, there are changes that we can observe. Consider the following characteristics of a chemical reaction.

  1. Chemical Reactions Can Cause Color Change
  2. Chemical reactions can form deposits
  3. Chemical Reactions Can Cause Changes in Temperature
  4. Chemical Reactions Can Cause Gas

Learn more

definition of The chemical reaction brainly.com/question/8922743

Characteristics of Chemical Reactions brainly.com/question/8922743

Details

Grade: High School

Subject: Chemistry

keywords: The chemical reaction

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If an automobile air bag has a volume of 11.6 ll , what mass of nan3nan3 (in gg ) is required to fully inflate the air bag upon
Tresset [83]

22.3 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.

To find the mass, the given data was,

Volume = 11.6 Liters

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A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

In airbags, sodium azide decomposes to form sodium and nitrogen gas, which inflates the bag. The decomposition reaction is:

2 NaN₃ ⇒ 2 Na + 3 N₂

We can calculate the mass of NaN₃ needed to produce 11.6 L of N₂ at STP, using the following relations.

  • At STP, 1 mole of N₂ occupies 22.4 L.
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Substituting all the known values to find the volume,

11.6 × ( 1 / 22.4) × ( 2/3) × ( 65.01 / 1)

= 22.4 g.

22.4 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.

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Answer:

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Explanation:

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Explanation:

Electrolysis of melt NaCl to form sodium (Na) metal and chlorine (Cl₂) gas.

This is a class of reaction called 'Decomposition Rxns'. For what it's worth, there are 6 distinct compound types that undergo breakdown by decomposition. The acronym C O A C H E can help remember them.

C - Carbonates => CaCO₃(s) => CaO + CO₂

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A - Acids (Oxoacids) => H₂CO₃(aq) => CO₂(g) + H₂O(l)

C - Chlorates, Bromates & Iodates => 2KClO₃(s) => 2KCl(s) + 3O₂(g)

H - Hydroxides => Ca(OH)₂(s) => CaO(s) + H₂O(l)

E - Electrolysis => see above electrolysis of NaCl(l)

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