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Anni [7]
3 years ago
6

How much energy is required to vaporize 14.27 grams of water at its boiling point? *

Chemistry
1 answer:
laila [671]3 years ago
6 0

Energy required to vaporize : 32.3 kJ

<h3>Further explanation </h3>

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

Mass of water = 14.27 g

Latent heat of vaporization ( boiling point of 100 ºC) :  2260 J/g

Energy required :

\tt Q=m.Lv\\\\Q=14.27\times 2260\\\\Q=32250.2~J\approx 32.3~kJ

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How can melting point and boiling point identify a substance
Nikolay [14]

Answer:

to determine of it is a solid liquid or gas.

Explanation:

The melting point is the temperature at which a substance converts from a solid state to a liquid state.

8 0
4 years ago
What is the concentration of a solution that is 0.25 moles of HCL added to 3.00L of water?
Lina20 [59]

Answer: 0.08 M

Explanation:

\text{molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}\\\\\text{molarity}=\frac{0.25}{3.00}\\\\\text{molarity}=\boxed{0.08 \text{ M}}

3 0
2 years ago
The element gallium has an atomic weight of 69.7 and consists of two stable isotopes gallium -69 and gallium -71. The isotope ga
BigorU [14]

Answer:

The answer to your question is Gallium-71 = 70.9202 amu

Explanation:

Gallium atomic weight = 69.7

Gallium-69 = 68.9 amu    abundance = 60.4%

Gallium-71 =     x                abundance = 39.6%  

To solve this problem just write an equation and solve it for the mass of gallium-71.

Equation

Gallium = Gallium-69(abundance) + Gallium-71(abundance)

Substitution

69.7 = (68.9)(0.604) + Gallium-71(0.396)

69.7 = 41.6156 + Gallium-71(0.396)

Gallium-71(0.396) = 69.7 - 41.6156

Gallium-71(0.396) = 28.0844

Gallium-71 = 28.0844/0.396

Gallium-71 = 70.9202 amu

3 0
3 years ago
How many moles of Fe2O3 will be produced from a 18.0 grams of Fe
Dennis_Churaev [7]

Answer:

The answer to your question is 0.113 moles of Fe₂O₃

Explanation:

Data

moles of Fe₂O₃ = ?

mass of Fe₂O₃ = 18 grams

Process

1.- Calculate the molar mass of Fe₂O₃

Fe₂O₃ = (56 x 2) + (16 x 3)

          = 112 + 48

          = 160 g

2.- Use proportions to solve this problem. The molar mass is equivalent to 1 mol.

                   160 g of Fe₂O₃ --------------- 1 mol

                     18 g of Fe₂O₃ ---------------- x

                            x = (18 x 1)/160

                           x = 0.113 moles of Fe₂O₃

6 0
3 years ago
Read 2 more answers
How many grams of Ar are there in 2.25 moles of Ar?
Arada [10]
There will be 89.865 grams of Ar. If you put it in sig figs, it will be rounded to 89.9g At.

5 0
4 years ago
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