Answer : I hope this helps !
The Effort Force is the force applied to a machine. Work input is the work done on a machine. The work input of a machine is equal to the effort force times the distance over which the effort force is exerted.
Answer:
Newton's second law
Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.
Explanation:
Answer:I believe it is D I might be wrong
Explanation:
Answer:
- The formula its
![f(t) \ = \ - \ 352 \ \frac{\$ }{years} \ t \ + \ \$ \ 2816](https://tex.z-dn.net/?f=f%28t%29%20%5C%20%3D%20%5C%20-%20%5C%20352%20%5C%20%5Cfrac%7B%5C%24%20%7D%7Byears%7D%20%5C%20t%20%5C%20%2B%20%5C%20%5C%24%20%5C%202816%20)
- After 5 years, the computer value its $ 1056
Explanation:
<h3>
Obtaining the formula</h3>
We wish to find a formula that
- Starts at 2816.
![f(0 \ years) \ = \ \$ \ 2816](https://tex.z-dn.net/?f=f%280%20%5C%20years%29%20%5C%20%3D%20%5C%20%5C%24%20%5C%202816)
- Reach 0 at 8 years.
![f( 8 \ years) \ = \ \$ \ 0](https://tex.z-dn.net/?f=f%28%208%20%5C%20years%29%20%5C%20%3D%20%5C%20%5C%24%20%5C%200)
- Depreciates at a constant rate. m
We can cover all this requisites with a straight-line equation. (an straigh-line its the only curve that has a constant rate of change) :
,
where m its the slope of the line and b give the place where the line intercepts the <em>y</em> axis.
So, we can use this formula with the data from our problem. For the first condition:
![f ( 0 \ years ) = m \ (0 \ years) + b = \$ \ 2816](https://tex.z-dn.net/?f=f%20%28%200%20%5C%20years%20%29%20%3D%20m%20%5C%20%280%20%5C%20years%29%20%2B%20b%20%3D%20%5C%24%20%5C%202816)
![b = \$ \ 2816](https://tex.z-dn.net/?f=%20b%20%3D%20%5C%24%20%5C%202816)
So, b = $ 2816.
Now, for the second condition:
![f ( 8 \ years ) = m \ (8 \ years) + \$ \ 2816 = \$ \ 0](https://tex.z-dn.net/?f=f%20%28%208%20%5C%20years%20%29%20%3D%20m%20%5C%20%288%20%5C%20years%29%20%2B%20%5C%24%20%5C%202816%20%3D%20%5C%24%20%5C%200)
![m \ (8 \ years) = \ - \$ \ 2816](https://tex.z-dn.net/?f=%20m%20%5C%20%288%20%5C%20years%29%20%3D%20%5C%20-%20%5C%24%20%5C%202816)
![m = \frac{\ - \$ \ 2816}{8 \ years}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cfrac%7B%5C%20-%20%5C%24%20%5C%202816%7D%7B8%20%5C%20years%7D)
![m = \frac{\ - \$ \ 2816}{8 \ years}](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cfrac%7B%5C%20-%20%5C%24%20%5C%202816%7D%7B8%20%5C%20years%7D)
![m = \ - \ 352 \frac{\$ }{years}](https://tex.z-dn.net/?f=%20m%20%3D%20%5C%20-%20%5C%20352%20%5Cfrac%7B%5C%24%20%7D%7Byears%7D)
So, our formula, finally, its:
![f(t) \ = \ - \ 352 \ \frac{\$ }{years} \ t \ + \ \$ \ 2816](https://tex.z-dn.net/?f=f%28t%29%20%5C%20%3D%20%5C%20-%20%5C%20352%20%5C%20%5Cfrac%7B%5C%24%20%7D%7Byears%7D%20%5C%20t%20%5C%20%2B%20%5C%20%5C%24%20%5C%202816%20)
<h3>After 5 years</h3>
Now, we just use <em>t = 5 years</em> in our formula
![f(5 \ years) \ = \ - \ 352 \ \frac{\$ }{years} \ 5 \ years \ + \ \$ \ 2816](https://tex.z-dn.net/?f=f%285%20%5C%20years%29%20%5C%20%3D%20%5C%20-%20%5C%20352%20%5C%20%5Cfrac%7B%5C%24%20%7D%7Byears%7D%20%5C%205%20%5C%20years%20%5C%20%2B%20%5C%20%5C%24%20%5C%202816%20)
![f(5 \ years) \ = \ - \$ \ 1760 + \ \$ \ 2816](https://tex.z-dn.net/?f=f%285%20%5C%20years%29%20%5C%20%3D%20%5C%20-%20%5C%24%20%5C%201760%20%2B%20%5C%20%5C%24%20%5C%202816%20)
![f(5 \ years) \ = $ \ 1056](https://tex.z-dn.net/?f=f%285%20%5C%20years%29%20%5C%20%3D%20%24%20%5C%201056%20)
The most common group of silicates is quartz. Silicate minerals is the most abundant mineral found in the crust. About 90% of the crust contains these minerals. Silicate minerals includes quartz, mica, feldspar, pyroxene, amphobole and olivine. About 12% of these silicates is quartz.