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3 years ago

[PICTURE ATTACHED] hellpp!

Chemistry

2 answers:

julsineya [31]3 years ago

6 0

Answer: Sure I’ll do it in the comments

Explanation:

Vinil7 [7]3 years ago

3 0

Answer:

I think it’s 2 and 3

Explanation:

If you look at the diagram it looks like three pushes the air up to 2 who then blows le air out.

(that’s how I would say it but I’m pretty sure that’s the answer)

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Which of these is an example of a physical change?

vladimir2022 [97]

Answer:

Their isn't your examples but I will give you mine

Freezing, Evaporation and so on.

6 0

3 years ago

A pharmacy intern is asked to prepare 3 L of a 30% w/v solution. T he pharmacy stocks the active ingredient in 8-ounce bottles o

MariettaO [177]

<u>Answer:</u> The number of bottles that will be needed are 6

<u>Explanation:</u>

We are given:

Amount of solution, the intern is asked to prepare = 3 L = 3000 mL (Conversion factor: 1 L = 1000 mL)

Strength of solution needed = 30 % (w/v)

This means that in 100 mL of solution, the solute present is 30 grams

So, in 3000 mL of solution, the solute present will be = $\frac{30}{100}\times 3000=900g$

Active ingredient present in 1 bottle = 8 ounce of 70 % (w/v)

<u>Conversion factor used:</u> 1 ounce = 29.57 mL

So, $8ounce\times \frac{29.57mL}{1ounce}=236.6mL$

Amount of active ingredient present in 1 bottle = $236.6\times \frac{70}{100}=165.6g$

To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:

$\text{Number of bottles}=\frac{\text{Amount of solution to prepare}}{\text{Amount of active ingredient in 1 bottle}}$

Putting values in above equation, we get:

$\text{Number of bottles}=\frac{900g}{165.6g}\\\\\text{Number of bottles}=5.43\approx 6$

Hence, the number of bottles that will be needed are 6

6 0

3 years ago

An atom has 38 protons and 42 neutrons it is ?

muminat

Answer:

The answer is, Strontium

4 0

3 years ago

Read 2 more answers

Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.

sashaice [31]

Answer:

0.00500M of Na₂C₂O₄

Explanation:

<em>When are dissolved in 150 mL of 1.0 M H2SO4.</em>

<em />

We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:

0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄

In 0.150L:

7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =

4 0

3 years ago

This equation is not balanced. Click on the coefficient we should change first.

Serga [27]

2 3 2 3 is what your gonna put in the blank spots

4 0

3 years ago