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zavuch27 [327]
3 years ago
15

A _____ is a short, fleshy stem surrounded by enlarged, fleshy bases of leaves.

Chemistry
2 answers:
aev [14]3 years ago
8 0

Answer:

bulb

Explanation:

emmasim [6.3K]3 years ago
3 0

Answer:

a. a bulb

Explanation:

I hope this helps hun!

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Si unit of heat and energy
lara31 [8.8K]

The answer is Joule.

7 0
3 years ago
Read 2 more answers
Balance <br> Si4H10+O2&gt;SiO2+H2O
Illusion [34]

Explanation: Si4H10+O2>SiO2+H2O

2Si4H10 + 13O2 = 8SiO2 + 10H2O

5 0
3 years ago
Min increases the temperature of a gas in an expandable container. If she keeps the pressure constant, what will happen to the v
Galina-37 [17]

Answer:

The volume will remain the same.

Explanation:

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law)

8 0
3 years ago
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The closeness of a measurement to its true value is a measure of its ____.
Mrrafil [7]

Answer: The closeness of a measurement to its true value is a measure of its accuracy.

Explanation:

Precision refers to the closeness of two or more measurements to each other. Example: If we measure weight four times and we get 60 kg each time. Then the measurement is very precise.

Accuracy refers to the closeness of a measured value to a standard or known value. Example: If the weight of the body is 60 kg and one person measures 58 kg and another person measures 59 kg. Then, the weight measured by second person is more accurate.

Thus the closeness of a measurement to its true value is a measure of its accuracy

8 0
3 years ago
what is the temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr if it occupies 13.3L at 55 degrees Celsius and 7
Rus_ich [418]

Answer:

3 °C

Explanation:

The pressure is constant, so this looks like a case where we can use Charles’ Law:

\frac{ V_{1} }{T_{1}} = \frac{V_{2} }{T_{2}}  

Invert both sides of the equation.

\frac{T_{1} }{V_{1}} = \frac{T_{2} }{V_{2}}

Multiply both sides by <em>V</em>₂

T_{2} = T_{1} \times \frac{V_{2} }{ V_{1} }

<em>V</em>₁ = 13.3 L; <em>T</em>₁ = (55 + 273.15) K = 328.15 K

<em>V</em>₂ = 11.2 L; <em>T</em>₂ = ?

T_{2} = \text{328.15 K} \times \frac{\text{11.2 L} }{\text{13.3 L}} = \text{276 K} = 3 ^{\circ}\text{C}

8 0
3 years ago
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