Answer:Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.
Explanation:
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Answer:
Q= 245 =2.5 * 10^2
Explanation:
ΔG = ΔGº + RTLnQ, so also ΔGº= - RTLnK
R= 8,314 J/molK, T=298K
ΔGº= - RTLnK = - 6659.3 J/mol = - 6.7 KJ/mol
ΔG = ΔGº + RTLnQ → -20.5KJ/mol = - 6.7 KJ/mol + 2.5KJ/mol* LnQ
→ 5.5 = LnQ → Q= 245 =2.5 * 10^2
Answer:
The rate of reaction will maintain constant
Explanation:
Rate of reaction is proportionate to rate constant x [A] ^2 x [B]. This means that the order of reaction with respect to C is 0 as it does not affect the rate of reaction as seen in the rate equation.
Essentially, order of reaction with respect to C is [C] ^0
Hence if [C] triples and becomes [3C]^0, the result will still be 1 as anything to the power of 0 is 1.
Therefore, the answer is that the rate of reaction will remain constant.
I don’t understand what your asking
