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kotykmax [81]
3 years ago
12

Which is the best example and explanation that a physical change has occurred?

Chemistry
2 answers:
Lostsunrise [7]3 years ago
6 0

Answer:

For the people wondering, yes, dicing potatoes is the correct answer. Because a new substance has not formed.

oee [108]3 years ago
4 0

dicing potatoes, because the molecules are separated but remain the same substance

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A sealed container of N2 gas has a pressure of 836 kPa at 54.7 ∘ C. After it is left out in the sun the pressure increases by 79
Anuta_ua [19.1K]
P1=836kPa
T1=54.7+273=327.7K
P2=836+79.9=915.9kPa
T2=?
T2=T1*P2/P1
=327.7*915.9/836
=359K=86 degree celsius
5 0
2 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
3 years ago
Give the major product formed when phenol is heated with concentrated H2SO4 and SO3. (There is more than one correct answer, but
iris [78.8K]

Answer:

See image attached and explanation

Explanation:

The reaction of phenol with SO3/H2SO4 is an electrophilic reaction. The electrophile attacks portions of high electron density in the substrate phenol.

The -OH group activates phenol towards electrophilic substitution at the ortho and para positions, hence the product(s) formed in this reaction(only one product is shown here as required by the question).

The sulphonation of phenol using concentrated sulfuric acid at lower temperature yields majorly the ortho product whereas at higher temperature the para product predominates.

4 0
3 years ago
Is the following chemical equation balanced?<br><br> 4Al + 3O2 2Al2O3<br><br> yes<br> no
PolarNik [594]

Answer:

Yes!

Explanation:

4Al + 3O2 -> 2Al2O3

4 Al's on the left side

6 O's on the left side

4 Al's on the right side

6 O's on the left side

This is balanced!  Let me know if you need help with any other equations.

4 0
3 years ago
Read 2 more answers
Pls help! DO NOT GIVE ME A LINK AS AN ANSWER!
melisa1 [442]

Answer:

(top to bottom)

0.50

0.63

0.83

1.0

1.3

2.5

Explanation:

8 0
3 years ago
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