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Dennis_Churaev [7]
3 years ago
13

How we can preserve the wetlands areas of nepal?​

Chemistry
1 answer:
Luden [163]3 years ago
7 0

Answer:

Reduce, reuse, and recycle your waste and trash. Protecting the environment helps protect the wetlands, especially since trash can make its way into the water. The best and easiest way to protect the environment is by limiting your household waste.

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Carbon dioxide (CO2) is the gas that is mainly responsible for global warming (the greenhouse effect). The burning of fossil fue
Nesterboy [21]

Answer:

1.7\cdot 10^{15} g

Explanation:

Glucose reacts with oxygen do produce carbon dioxide and water:

C_6H_12O_6 (s) + 6 O_2 (g)\rightarrow 6 CO_2 (g) + 6 H_2O (l)

Given a daily mass of glucose:

m_1 = 5.0\cdot 10^2 g

Find moles of glucose:

n_1 = {5.0\cdot 10^2 g}{180.156 g/mol} = 2.775 mol

From stoichiometry of this equation, moles of carbon dioxide can be found by multiplying this amount by 6:

n_2 = 2.775 mol\cdot 6=16.65 mol

Convert this into mass using the molar mass of carbon dioxide:

m_2 = 16.65 mol\cdot 44.01 g/mol = 732.8 g

This is the mass of carbon dioxide per person per day. Multiply by the population and by the number of days to get the total mass:

732.8 \frac{g}{person\cdot day}\cdot 365 days\cdot 6.5\cdot 10^9 people = 1.7\cdot 10^{15} g

5 0
3 years ago
Bond order of n2<br><br>bond order of N2 ​
snow_lady [41]

Answer:

The MO method for N2+ gives the bond order equal to 2.5. But first, we look at the diagram of molecular orbitals for N2 (the bond order for the nitrogen molecule is 3). the N2+ molecule). That is, the bond order for N2+ is 2.5.

4 0
3 years ago
Clay and water make a ______<br><br> a. solution<br> b.suspension<br> c. colloid
jeka57 [31]

Answer:

colloid

Explanation:

3 0
3 years ago
Consider the following intermediate chemical equations.
QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

P_4(s)+6Cl_2\rightarrow 4PCl_3  \Delta H_1=-2439kJ (1)

4PCl_5(g)\rightarrow P_4(s)+10Cl_2(g)  \Delta H_2=3438kJ (2)

Net chemical equation:

PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H=? (3)

Adding 1 and 2 we get,

4PCl_5(g)\rightarrow 4PCl_3(g)+4Cl_2 \Delta H_3=\Delta H_1+\Delta H_2=-2439+3438=1000kJ   (4)

Now dividing equation (4) by 4, we get

PCl_5(g)\rightarrow PCl_3(g)+Cl_2

\Delta H=\frac{\Delta H_3}{4}=\frac{1000kJ}{4}=250kJ   (4)

8 0
3 years ago
λmax for the π → π* transition in ethylene is 170 nm. Is the HOMO-LUMO energy difference in ethylene greater than or less than t
-Dominant- [34]

Answer:

the HOMO-LUMO energy difference in ethylene is greater than that of cis,trans−1,3−cyclooctadiene

Explanation:

The λmax is the wavelength of maximum absorption. We could use it to calculate the HOMO-LUMO energy difference as follows:

For ethylene

E= hc/λ= 6.63×10^-34×3×10^8/170×10^-9= 1.17×10^-18J

For cis,trans−1,3−cyclooctadiene

E= hc/λ=6.63×10^-34×3×10^8/230×10^-9=8.6×10^-19J

Therefore, the HOMO-LUMO energy difference in ethylene is greater than that of cis,trans−1,3−cyclooctadiene

8 0
3 years ago
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