The balanced equation for the above reaction is as follows;
4HCl + O₂ ---> 2H₂O + 2Cl₂
stoichiometry of HCl to O₂ is 4:1
number of HCl moles present - 63.1 g / 36.5 g/mol = 1.73 mol
number of O₂ moles present - 17.2 g / 32 g/mol = 0.54 mol
if HCl is the limiting reactant; then number of O₂ moles = 1.73/4 = 0.43 mol
There are 0.54 mol present and only 0.43 mol are required to react. Therefore HCl is the limiting reactant and O₂ is in excess.
For getting the result of this problem, the knowledge of periodic table is very important. From the periodic table we come to know that. The knowledge of atomic mass of magnesium is also required to solve the problem.
1 mole of magnesium = 24.3 gm
88.1 moles of magnesium = (24.3 * 88.1) gms
= 2140.83 gms
So 2140.83 grams are there in 88.1 moles of magnesium.
Answer:
Less than 7 ph value are acidic. Greater than 7 ph value are basic.
Answer:
V1= 0.305L
Explanation:
To find the initial volume of 1.25M potassium fluoride needed to make tge dilution specified in the question, we can use: C1 × V1 = C2 × V2
Since the question wants the volume in litres, convert 455 mL to L
455/ 1000
= 0.455 L
Now make the substitution
1.25 × V1 = 0.838 × 0.455
Rearrange to make V1 the subject
V1=
Answer:
will form bonds between atoms. for more details are in the pic
